The total energy stored in the capacitors is determined as 2.41 x 10⁻⁴ J.
<h3>What is the potential difference of the circuit?</h3>
The potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
where;
- C is capacitance of the capacitor
- V is the potential difference
For a parallel circuit the voltage in the circuit is always the same.
The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
2U = CV²
V = √2U/C
V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)
V = 12 V
The equivalent capacitance of C1 and C2 is calculated as follows;
1/C = 1/C₁ + 1/C₂
1/C = (1)/(0.9 x 10⁻⁶) + (1)/(16 x 10⁻⁶)
1/C = 1,173,611.11
C = 1/1,173,611.11
C = 8.52 x 10⁻⁷ C
The total capacitance of the circuit is calculated as follows;
Ct = 8.52 x 10⁻⁷ C + 2.5 x 10⁻⁶ C
Ct = 3.35 x 10⁻⁶ C
The total energy of the circuit is calculated as follows;
U = ¹/₂CtV²
U = ¹/₂(3.35 x 10⁻⁶ )(12)²
U = 2.41 x 10⁻⁴ J
Learn more about energy stored in a capacitor here: brainly.com/question/14811408
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Answer:
B
Explanation:
Heat energy of a substace can be calculated using
Q = mcθ
where Q = Heat energy
m =mass
c = specific heat capacity
θ =temperature difference
Temperature difference is final temperature - initial temperature.
So we get,
Q = 1 × 600×(100-20)
= 48000 J
There are an estimated 100 billion, so the answer would be D.) Billions
This effect is explained by increased chain entanglements at higher molecular weights. Increasing the degree of crystallinity of a semicrystalline polymer leads to an enhancement of the tensile strength. Deformation by drawing increases the tensile strength of a semicrystalline polymer.
Answer:
The rate of increase of the energy content of the room when all the eletrical devices are on is 1650 W.
Explanation:
From conservation of energy,
Rate of energy transfer (
) = Rate of change of energy within the room (
).
As according to the problem no heat transfer occurs through the walls of the room we can assume that there is no energy transferred to the outside of the room, i.e., 
.
If all the electric devices are on inside the room, then the rate of increase of energy is equal to the power (
) consumed bt the electrical devices inside the room. Therefore we can write,
