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3 years ago

which is the of these their statements correctly describes a key difference between aerobic activity and anaerobic activity

Physics

1 answer:

KATRIN_1 [288]3 years ago

8 0

Aerobic uses oxygen to liberate heat while anaerobic is in the absence of oxygen.

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Mike took less time to run the 100 meters than mitchell what does this tell us about his speed

Dahasolnce [82]

Mike was running at a higher speed than Mitchell

8 0

3 years ago

Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

frez [133]

Answer:

1.49 x $10^{11}$

Explanation:

Kepler's third law states that The square of the orbital period of a planet is directly proportional to the cube of its orbit.

Mathematically, this can be stated as

$T^{2}$ ∝ $R^{3}$

to remove the proportionality sign we introduce a constant

$T^{2}$ = k $R^{3}$

k = $\frac{T^{2} }{R^{3} }$

Where T is the orbital period,

and R is the orbit around the sun.

For mars,

T = 687 days

R = 2.279 x $10^{11}$

for mars, constant k will be

k = $\frac{687^{2} }{(2.279*10^{11}) ^{3} }$ = 3.987 x $10^{-29}$

For Earth, orbital period T is 365 days, therefore

$365^{2}$ = 3.987 x $10^{-29}$ x $R^{3}$

$R^{3}$ = 3.34 x $10^{33}$

R = 1.49 x $10^{11}$

8 0

3 years ago

Read 2 more answers

Suppose a scoentist was able to construct a barometer with a liquid being denser than mercury , then how high would the liquid r

ki77a [65]

Answer:

the liquid has less height than the mercury

h_{ liquid} = $\frac{\rho_{Hg} }{\rho_{liqid}} \ h_{Hg}$

Explanation:

The pressure as a function of the height is given by

P = ρ g h

where ρ is the density of the liquid, g the acceleration of gravity and h the height reached by the column of the liquid

In that case they say that the pressure is the standard one that is P = 1.01 10⁵ Pa = 760 mmHg

The first way to give the pressure is in SI units and the second way is the height that the mercury column reaches

In the case of building a barometer with a liquid that has a density greater than that of mercury

ρ_liquid > ρ_Hg

the pressure

P =ρ_lquid g h_liquid

if we have the same pressure

ρ_{Hg} g h_{Hg} = ρ_{liquid} g h_{liquid}

h_{ liquid} = $\frac{\rho_{Hg} }{\rho_{liqid}} \ h_{Hg}$

therefore the liquid has less height than the mercury

7 0

3 years ago

On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per

Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

$V_{avg} = \frac{Final \ position\ - \ Initial \ position}{final \ time\ - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\ - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr$

Therefore, the average velocity is 180 km/hr

3 0

3 years ago

E fundamental frequency of an open organ pipe corresponds to the middle c (261.6 hz on the chromatic musical scale). the third r

luda_lava [24]

The wavelength of the third resonance of the closed organ pipe is equal to the ratio between the speed of sound and the frequency of the 3rd harmonic:

$\lambda_3 = \frac{c}{f_3}=\frac{343 m/s}{261.6 Hz} =1.31 m$

The relationship between length of a closed pipe and wavelength of the standing waves inside is:

$L=\frac{n}{4}\lambda_n$

where n is the number of the harmonic. In this case, n=3, so the length of the pipe is

$L=\frac{3}{4}(1.31 m)=0.98 m$

8 0

3 years ago