All categories

3 years ago

7. What determines whether a charged object gains or loses electrons?

Physics

2 answers:

fgiga [73]3 years ago

6 0

Hello there.

11. Static charge is dissipated through static electricity.

EleoNora [17]3 years ago

3 0

7. The charged object can have two polarities, positive or negative which is determined by the configuration of electron orbitals of the material. If there are free orbitals, it will likely gain electrons and produce a negative charge. If there are free electrons on the outermost orbitals, these electrons will be lost and the material will have a positive charge.

8. Rubbing styrene and rabbit fur because rabbit fur has free orbitals which can hold electrons making styrene positive.

9. When it is dry and windy.

10. When there no other materials that can take or add electrons from or to it.

11. Static charge is dissipated through static electricity.

You might be interested in

A man is flying in a hot-air balloon in a straight line at a constant rate of 5 feet per second, while keeping it at a constant

icang [17]

Answer:

$x = 220.85 ft$

Explanation:

Let at any moment of time the friend's car is at some horizontal distance "x" from the position of balloon.

Now if the altitude of the balloon is fixed and it is at height "h"

so here we will have

$tan \theta = \frac{h}{x}$

now we know that

initially the angle of the friend's car is 35 degree

so the horizontal distance will be

$x_1 = h cot35$

similarly if the angle after passing the car position is 36 degree

then we have

$x_2 = h cot36$

now the speed of the balloon is constant

so we have

$v = \frac{x_1 + x_2}{\Delta t}$

$5 ft/s = \frac{h cot35 + h cot36}{90 s}$

$5 ft/s = \frac{2.8h}{90}$

$h = 160.45 ft$

so the final position of friend when the angle is 36 degree

$x = \frac{h}{tan36}$

$x = \frac{160.45}{tan36}$

$x = 220.85 ft$

4 0

3 years ago

Problem: The circular blad on a radial arm saw is turning at262

kobusy [5.1K]

Answer:

Net torque, $\tau=-0.033\ N-m$

Explanation:

It is given that,

Initial angular speed of the blade, $\omega_i=262\ rad/s$

Final angular speed of the blade, $\omega_f=85\ rad/s$

Time, t = 18 s

Radius of the disk, r = 0.13 m

Mass of the disk, m = 0.4 kg

We need to find the net torque applied to the blade. We know that in rotational mechanics the net torque acting on an object is equal to the product of moment of inertia and the angular acceleration such that,

$\tau=I\times \alpha$

The moment of inertia of the disk, $I=\dfrac{mr^2}{2}$

$\tau=\dfrac{mr^2}{2}\times \dfrac{\omega_f-\omega_i}{t}$

$\tau=\dfrac{0.4\times (0.13)^2}{2}\times \dfrac{85-262}{18}$

$\tau=-0.033\ N-m$

Negative sign shows that the net torque is acting in the opposite direction of its motion. Hence, this is the required solution.

3 0

3 years ago

Which best describes why scientific models change over time?

irina1246 [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices and the answer is B.
a.) Models can be changed by scientists who are more famous than previous scientists.
b.) As technology advances, new experiments often expose problems in accepted theories. 
c.) Scientists tend to value new theories because they are more exciting. 
d.) A newer theory is more valid because it uses more mathematics.

6 0

4 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$