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4 years ago

7. What determines whether a charged object gains or loses electrons?

Physics

2 answers:

fgiga [73]4 years ago

6 0

Hello there.

11. Static charge is dissipated through static electricity.

EleoNora [17]4 years ago

3 0

7. The charged object can have two polarities, positive or negative which is determined by the configuration of electron orbitals of the material. If there are free orbitals, it will likely gain electrons and produce a negative charge. If there are free electrons on the outermost orbitals, these electrons will be lost and the material will have a positive charge.

8. R<span>ubbing styrene and rabbit fur because rabbit fur has free orbitals which can hold electrons making styrene positive.

9. When it is dry and windy.

10. When there no other materials that can take or add electrons from or to it.

11. Static charge is dissipated through static electricity.
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"The work done on an ideal gas system in an isothermal process is -400 J. What is the change in internal (thermal) energy of the

Archy [21]

Answer:

zero

Explanation:

Work done = - 400 J

In an isothermal process, the temperature remains constant. So, according to the first law of thermodynamics

dQ = dU + dW

As the temperature remains constant and the change in internal energy is the function of change in temperature, here change is temperature is zero so the change in internal energy is also zero.

6 0

4 years ago

The greatest ocean depths on the Earth are found in the Marianas Trench near the Philippines. Calculate the pressure (in atm) du

frozen [14]

Answer:

$P = 103867260$ atm

Explanation:

The pressure at the bottom of any liquid column is equal to product of density of the liquid , gravitational acceleration constant (g) and height of the water column

Thus, $P = \rho*g*h$

Substituting the given values, we get -

$P = 1029$ kg/m3 $* 9.8$ m/s^2 $*10.3 *1000$ meters

$P = 103867260$ atm

8 0

3 years ago

A rare butterfly (0.01 kg) is slowly flapping its wings and moving across a road. An unsuspecting driver in a large car (1000 kg

aliya0001 [1]

Both the butterfly and the large car will have equal forces but in opposite direction.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.

Fa = - Fb

where;

Fa is the force exerted by the large car
Fb is the force of the butterfly

Thus, both the butterfly and the large car will have equal forces but in opposite direction.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

#SPJ1

8 0

2 years ago

Tcecarenko [31]

Explanation:

Melting point

Boiling point

Does the compound

dissolve in water?

Can the compound

conduct electricity?

8 0

3 years ago

A mass of 0.75 kilograms is attached to a spring/mass oscillator. A force of 5 newtons is required to stretch the spring 0.5 met

zlopas [31]

Answer:

b > 66.41 kg/s

Explanation:

The spring force F = -kx, where k = spring constant, the damping force f = -bv. The net force F' = F + f

F + f = ma

-kx - bv = ma

-kx -bdx/dt = md²x/dt².

Re-arranging the equation, we have

So, md²x/dt² + bdx/dt + kx = 0

Dividing through by m, we have

d²x/dt² + (b/m)dx/dt + (k/m)x = 0

This is a second-order differential equation. The characteristic equation is thus,

D² + (b/m)D + (k/m) = 0

Using the quadratic formula, we find D.

$D = \frac{-(b/m) +/- \sqrt{(b/m)^{2} - 4k/m} }{2}$

For an overdamped system,

$(b/m)^{2} - 4k/m} > 0$

$(b/m)^{2} > 4k/m}\\(b/m) > \sqrt{4k/m}} \\(b/m) > 2\sqrt{k/m}} \\b > 2\sqrt{km}}$

Now, k = F/x. Since the weight of the object causes the spring to stretch a distance of 0.5 m, k = mg/x where m = mass of object = 0.75 kg, g = 9.8 m/s² and x = x₀ =0.5 m.

Substituting k = mg/x into the inequality for b, we have

b > 2√{(mg/x₀)m}

b > 2√{(m²g/x₀)}

b > 2m√{g/x₀)}

b > 2 × 0.75 kg√{9.8 m/s²/0.5 m)}

b > 1.5 kg√{19.6/s²)}

b > 1.5 kg × 4.427/s

b > 66.41 kg/s

6 0

3 years ago