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antiseptic1488 [7]
3 years ago
5

An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bush

es 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?
Physics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

Tan theta = 9 / 90 = .1      so theta = 5.71 deg

The time for the monkey to reach the ground is

t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec

So the horizontal speed of the dart must be at least

Vx = 90 m / 1.36 sec = 66.4 m/s

Vx = V cos theta

V = 66.4 m/s / cos 5.71 = 66.7 m/s

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Answer:

D. None of the above

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T-mg cos \theta = m\frac{v^2}{r}\\T=m\frac{v^2}{r}+mg cos \theta

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v is the speed of the pendulum

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From the formula we see that the value of the tension, T, depends only on the value of v (the speed) and \theta, the angle. We notice that:

- Since \theta and v constantly change, T must change as well

- At \theta=0^{\circ} (equilibrium position), cos \theta=1 (maximum value), and also the speed v is maximum, so the tension has the maximum value at the equilibrium position

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