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prohojiy [21]
3 years ago
11

Discuss the function of cobalt in action of vitamin B12 and its derivatives and how cobaloximes serve as models for the biologic

al system.
Chemistry
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

Cobalt and its derivatives act as a catalyst for some enzymatic functions, in this case, it acts as a cofactor.

Cobaloximes are effective electrocatalysts for the production of hydrogen and, therefore, functional models for hydrogenases.

Explanation:

Cobalt is a metal that participates directly in the synthesis of vitamin B12, necessary for the metabolism of various proteins, with megaloblastic anemia being one of the greatest evidences of a lack.

Its main function is that it integrates the vitamin B12 molecule, also called cyanocobalamin, so that lack of cobalt causes the same symptoms as vitamin B12 deficiency.

Vitamin B12 can only be synthesized by bacteria and for this a cobalt atom is required, in fact adult ruminants can synthesize enough vitamin B12 in the rumen provided they have an adequate supply of cobalt.

It acts as a catalyst for some enzymatic functions, in this case, it acts as a cofactor. Very important for example in the transfer of methyl groups, in this way cobalt, together with folic acid participate in the synthesis of methionine.

The dimethylglioxime (dmgH) complexes to the cobalt to give a series of complexes of Co (III), called cobaloxime, that having 4 positions coordinated to nitrogen in a coplanar way and forming a ring similar to the corrínico nucleus; If another substituent also has an N-heterocyclic nature, it can correctly simulate the B12 system.

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Fertile offspring mate is a form of reproduction
6 0
3 years ago
What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c​
marissa [1.9K]

Answer:

\boxed{\text{922 mL}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 693 mL; T₁ =  45 °C

V₂ = ?;           T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = (  45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}

5 0
3 years ago
What is the temperature (°C) of 1.75 g of O2 gas occupying 4.60 L at 1.00 atm?
julsineya [31]

Given- m= 1.75 g  

Now moles of O2 gas= Mass/ Molar mass  

n = 1.75/32  

V= 2L  

P= 1atm  

R=0.0821.....Constant  

As PV=nRT  

=> T=PV/nR  

= 1* 2/ (1.75/32)*0.0821 K  

= 2*32/1.75* 0.0821 K  

= 445.45 K  

= (445.45- 273.15) degrees celsius  

= 172.30 degrees celsius..... ANSWER

4 0
3 years ago
Consider the reaction described by the following chemical equation.
oee [108]

Answer:

Q = -897 kJ/mol

Explanation:

From the given information:

The heat released Q = -65.9 kJ

To start with the molar mass of H_2O_2 = 2 × (molar mass of H) + 2 × (molar mass of O)

= (2 × 1.008) + (2 × 16.0 )

= 34.016 g/mol

However, given that:

mass of H_2O_2  2.50 g

The number of moles of H_2O_2  = \dfrac{mass}{molar \ mass}

= \dfrac{2.5}{34.016}

= 7.349 \times 10^{-2} \ mol

Finally; Using the formula:

\Delta H = \dfrac{Q}{number \ of \ moles}\\ \\ Q = \dfrac{-65.9 \ kJ}{7.349 \times 10^{-2} \ mol}

Q = -897 kJ/mol

6 0
2 years ago
Which arrow or arrows indicate a process that cycles carbon from living or nonliving organisms? Describe the process or processe
serg [7]

Answer:

A

Explanation:

3 0
3 years ago
Read 2 more answers
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