What is the electron configuration of an element with atomic number 15? A. 1s2 2s2 2p6 B. 1s2 2s2 2p6 3s2 3p5 C. 1s2 2s2 2p6 3s2
2 answers:
Answer: The correct answer is option C.
Explanation:
Electronic configuration of an element is defined as the distribution of electrons in sub-shells of an element.
We are given an element of atomic number 15.
We know that,
Atomic number = Number of electrons = Number of protons
Number of electrons = 15
For filling of electrons, the orbitals of lower energy will be filled first. The filling of orbitals follow the pattern: 1s, 2s, 2p, 3s, 3p, 4s, 3d and so on..
So, the electronic configuration of element having atomic number 15 is:
Hence, the correct answer is Option C.
You might be interested in
Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P× V = n× R× T
In this case, you know:
- P= 2 atm
- V= ?
- n=
being 2g/mole the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
- R= 0.082
- T= 353 K
Replacing:
2 atm× V = 4.745 moles× 0.082× 353 K
Solving:
V = (4.745 moles× 0.082× 353 K)÷ 2 atm
<u><em>V= 68.67 L</em></u>
Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
Learn more: