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svetlana [45]
3 years ago
6

What is the electron configuration of an element with atomic number 15? A. 1s2 2s2 2p6 B. 1s2 2s2 2p6 3s2 3p5 C. 1s2 2s2 2p6 3s2

3p3 D. 1s2 2s2 2p6 3s2 E. 1s2 2s2 2p6 3p3 3s2 3p1
Chemistry
2 answers:
Kamila [148]3 years ago
5 0

Answer: The correct answer is option C.

Explanation:

Electronic configuration of an element is defined as the distribution of electrons in sub-shells of an element.

We are given an element of atomic number 15.

We know that,

Atomic number = Number of electrons = Number of protons

Number of electrons = 15

For filling of electrons, the orbitals of lower energy will be filled first. The filling of orbitals follow the pattern: 1s, 2s, 2p, 3s, 3p, 4s, 3d and so on..

So, the electronic configuration of element having atomic number 15 is: 1s^22s^22p^63s^23p^3

Hence, the correct answer is Option C.

kipiarov [429]3 years ago
4 0
B 
hopes this helps!!!!!!!!!
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B) 1-propanol has more hydrogen bonding than ethyl methyl ether.

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1-propanol and ethyl methyl ether look very similar but have very different boiling points. They both have three carbon atoms but ethyl methyl ether has an oxygen atom.

Ethyl methyl ether has both London dispersion forces and dipole-dipole interactions.

1-Propanol has London dispersion forces, dipole-dipole interactions and hydrogen bonding.

1-propanol has more hydrogen bonding than ethyl methyl ether which explains why they both have different boiling points.

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Lisa’s book measures 40 cm x 10 cm x 2 cm. What is the volume of her book
White raven [17]

\text{Hello there! :)}

\large\boxed{V = 800cm^{3} }

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Suppose a sample of gas is composed of 100 molecules, with speeds given below. Speed (m/s) Number 200 23 400 42 600 26 800 8 100
ollegr [7]

Answer:

The answer is:

speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23  \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42  \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26  \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8  \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1  \\\\

Explanation:

Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.

Average speed for 1st option:

= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\  \frac{m}{s} \ \ \ \  \ \ \ \ \ \text{average speed of gas}

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 = \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}

 Average speed for 3rd option:

= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}

 Average speed for 4th option:

 = \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\  \frac{m}{s}

  Average speed for 5th option:

= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}

The average speed also increased by half because the temperatures had kinetic energy.\to 444 \ \frac{m}{s}\  to \ 222 \ \frac{m}{s}

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