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svetlana [45]
3 years ago
6

What is the electron configuration of an element with atomic number 15? A. 1s2 2s2 2p6 B. 1s2 2s2 2p6 3s2 3p5 C. 1s2 2s2 2p6 3s2

3p3 D. 1s2 2s2 2p6 3s2 E. 1s2 2s2 2p6 3p3 3s2 3p1
Chemistry
2 answers:
Kamila [148]3 years ago
5 0

Answer: The correct answer is option C.

Explanation:

Electronic configuration of an element is defined as the distribution of electrons in sub-shells of an element.

We are given an element of atomic number 15.

We know that,

Atomic number = Number of electrons = Number of protons

Number of electrons = 15

For filling of electrons, the orbitals of lower energy will be filled first. The filling of orbitals follow the pattern: 1s, 2s, 2p, 3s, 3p, 4s, 3d and so on..

So, the electronic configuration of element having atomic number 15 is: 1s^22s^22p^63s^23p^3

Hence, the correct answer is Option C.

kipiarov [429]3 years ago
4 0
B 
hopes this helps!!!!!!!!!
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Methanol, ethanol, and n−propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is lib
Sergeeva-Olga [200]

Answer:

a) Heat of combustion of 1 g of methanol = -22.6 kJ = (-2.26 × 10) kJ

b) Heat of combustion of 1 g of ethanol = -29.7 kJ = (-2.97 × 10) kJ

c) Heat of combustion of 1 g of propanol = -33.5 kJ = (-3.35 × 10) kJ

Explanation:

a) The equation for the combustion of methanol is given as

CH₃OH + (3/2)O₂ → CO₂ + 2H₂O

The standard heat of combustion of methanol is given as -726 kJ/mol from literature.

But, 1 g of methanol will have the heat of combustion of the number of moles of methanol contained in 1 g of methanol.

Number of moles = (mass)/(molar mass)

Molar mass of (CH₃OH) = 32.04 g/mol

Number of moles = (1/32.04) = 0.03121 moles

1 mole of methanol has a heat of combustion of -726 kJ

0.03121 mole of methanol will have a heat of combustion of (0.03121 × -726) = -22.6 kJ

b) The equation for the combustion of ethanol is given as

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

The standard heat of combustion of ethanol is given as -1367.6 kJ/mol from literature.

But, 1 g of ethanol will have the heat of combustion of the number of moles of ethanol contained in 1 g of ethanol.

Number of moles = (mass)/(molar mass)

Molar mass of (C₂H₅OH) = 46.07 g/mol

Number of moles = (1/46.07) = 0.0217 moles

1 mole of ethanol has a heat of combustion of -1367.6 kJ

0.0217 mole of ethanol will have a heat of combustion of (0.03121 × -1367.6) = -29.7 kJ

c) The equation for the combustion of propanol is given as

C₃H₇OH + (9/2)O₂ → 3CO₂ + 4H₂O

The standard heat of combustion of propanol is given as -2020 kJ/mol from literature.

But, 1 g of propanol will have the heat of combustion of the number of moles of propanol contained in 1 g of propanol.

Number of moles = (mass)/(molar mass)

Molar mass of (C₃H₇OH) = 60.09 g/mol

Number of moles = (1/60.09) = 0.0166 moles

1 mole of propanol has a heat of combustion of -2020 kJ

0.0166 mole of propanol will have a heat of combustion of (0.0166 × -2020) = -33.5 kJ

Hope this Helps!!!

5 0
3 years ago
Why is the table salt considered to be a compound, while sodium is not??
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Answer:

Table salt is considered to be a compound because it is made up of two elements (sodium and chloride,) while sodium itself is a raw element. That's why table salt is considered to be a compound, while sodium is not.

Hope this helped, have a nice day! :)

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3 years ago
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Answer:

Answer to the following question is as follows;

Explanation:

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1 ml = 1 cm³

1000 ml = 1 liter

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Not sure but Maybe a “value and a unit”
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