The solution would be like this for this specific problem:
4 NaOCl + S2O3{2-} + 2
OH{-} → 2 SO4{2-} + H2O + 4 NaCl
<span>(0.00456 L) x (0.100 mol/L
S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>
<span>(5.00 mL) x (1.08 g/mL) =
5.40 g solution </span>
(0.54313 g) / (5.40 g) =
0.101 = 10.1%
So, the average percent by mass of NaClO in the
commercial bleach is 10.1%.
An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation :
First we have to calculate the moles of 
Now we have to calculate the moles of 
The balanced chemical reaction is,
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 3 mole of
So, 
moles of react to give 
moles of
Now we have to calculate the mass of
Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
D.
This is in accordance with the law of conservation of energy.
