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Ber [7]
2 years ago
6

Which of the following giant covalent structures does not have a high melting and boiling

Chemistry
2 answers:
iogann1982 [59]2 years ago
6 0

Answer:

Polythene has the lowest melting/boiling point from all the other covalent structures mentioned in this question.

vaieri [72.5K]2 years ago
5 0

Answer:

Polythene (polyethene according the IUPAC nomenclature.)

Explanation:

Consider the structure of each option:

  • Polythene: long chains of atoms that are able to rotate along the bonding axis.
  • Graphite: layers of (hexagonal) carbon sheets; each individual sheet is rigid (allows no rotation.)
  • Silicon dioxide: three-dimensional (tetrahedral) network of carbon and oxygen atoms; the entire network very rigid (allows no rotation.)
  • Diamond: three-dimensional (tetrahedral) network of carbon atoms; likewise, the entire tetrahedral network is very rigid.

Melting each structure requires overcoming the forces that hold the structure rigid:

  • In polythene, van der Waal forces hold the chains together and prevents rotations.
  • Deshaping graphite requires bending the layers; doing so would require overcoming the covalent bonds within the hexagonal sheets.
  • In silicon dioxide and diamond, deshaping the tetrahedral network also requires overcoming covalent bonds.

Van der Waal forces are much easier to break than covalent bonds.

Hence, the melting point of polythene would be the lowest among the options.

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The three beakers shown below contain solutions of [cof6]3–, [co(nh3)6]3+, and [co(cn)6]3–. based on the colors of the three sol
vitfil [10]
[Co(CN)₆]³⁻ → Yellow
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.

- Ligands strength order:     CN⁻ > NH₃ > F⁻ 

- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻

- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.

- So CN complex will absorb at lower wavelength (yellow color)
3 0
3 years ago
If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n
Harman [31]

Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

to learn more about Limiting Reagent go to - brainly.com/question/14222359

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4 0
1 year ago
Potassium chlorate is a white, crystalline solid. It can be broken down into potassium chloride (a salt)
lions [1.4K]

Answer:

Notice that the number of atoms of

K

and

Cl

are the same on both sides, but the numbers of

O

atoms are not. There are 3

O

atoms on the the left side and 2 on the right. 3 and 2 are factors of 6, so add coefficients so that there are 6

O

atoms on both sides.

2KClO

3

(

s

)

+ heat

→

KCl(s)

+

3O

2

(

g

)

Now the

K

and

Cl

atoms are not balanced. There are 2 of each on the left and 1 of each on the right. Add a coefficient of 2 in front of

KCl

.

2KClO

3

(

s

)

+ heat

→

2KCl(s)

+

3O

2

(

g

)

The equation is now balanced with 2

K

atoms,

7 0
3 years ago
Read 2 more answers
Examine the statement about alchemy
Arturiano [62]

Answer: B.

Explanation:

7 0
3 years ago
Analyze: The metallic character of an element is determined by how readily it loses electrons. Elements that lose electrons most
GenaCL600 [577]

Answer:

Group 1 or akali metals have the greatest metallic property.

Group 17 has the lowest metallic character.

C. As you move from right to lefton the periodic table, metallic character increases which is the ability to lose electrons. Ionization energy decrease as we move from right to left on the periodic table.

Explanation:

Akali metals in group 1 have the greatest metallic property and they are the most reactive metals. Francium metal on the group has the most metallic characteristics. It is rare and very radioactive. Group 17 has the lowest metallic character. This is because while moving across the period, the number of electrons in the outermost shell increases. This make it difficult for atoms to leave see electrons and become electropositive . Group 17 has the highest tendency of accepting electrons.

Ionization energy is the energy use to remove electron from an atom in gaseous stage. Ionization energy decrease as we move from right to left on the periodic table and metallic character increases as we move from right to left on the periodic table.

5 0
3 years ago
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