Answer:
The number of turns of wire needed is 573.8 turns
Explanation:
Given;
maximum emf of the generator, = 190 V
angular speed of the generator, ω = 3800 rev/min =
area of the coil, A = 0.016 m²
magnetic field, B = 0.052 T
The number of turns of the generator is calculated as;
emf = NABω
where;
N is the number of turns


Therefore, the number of turns of wire needed is 573.8 turns
To find the average of data collected, add all of the measurements: 5.9+6.2+6.3+6= 12.2
Then, divide the total amount by the number of data collected which is 4: 12.2/4= 3.05
The average speed of the runner of the race is approximately 3.05 km/min
Feel free to ask me any other questions you might have :)
I need a picture please befor i can answer
Initial Velocity = 0
Final Velocity=3
Duration of time=0.5
Acceleration=6
I hope that helped. Good luck!