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3 years ago

Explain what happens to the particles in a substance during a physical change.

Physics

2 answers:

omeli [17]3 years ago

7 0

Answer:

In physical changes no new materials are formed and the particles do not change apart from gaining or losing energy. ... Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas. Only their arrangement, energy and movement changes.

Explanation:

Hope this helps

Soloha48 [4]3 years ago

4 0

Answer:

During Physical Change there would be a re-arrangements of atoms or molecules, changes of the arrangement may be change in the distance between atoms or molecules, change in the crystal form, .....etc

Explanation:

A physical change is any change not involving a change in the substance's chemical identity. Matter undergoes chemical change when the composition of the substances changes: one or more substances combine or break up (as in a relationship) to form new substances.Physical changes occur when objects undergo a change that does not change their chemical nature. A physical change involves a change in physical properties. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density.

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A graduated cylinder is filled with water to the 24-mL mark. When a rock is placed in the cylinder, the level rises to the 53-mL

harkovskaia [24]

30ml is the correct answer to your question hope i can help

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3 years ago

A boy on the edge of a vertical cliff 20-m high throws a stone horizontally outwards with a speed of 20 m/s. It strikes the grou

Komok [63]

Answer:

Horizontal distance from the foot of the cliff is 40 m

Explanation:

Given :

Speed of stone $v = 20\frac{m}{s}$

Vertical distance $d = 20$ m

Gravitational acceleration $g = 10$ $\frac{m}{s^{2} }$

From the kinematics equation,

$d = v_{o} t + \frac{1}{2} at^{2}$

Where $v_{o} =$ initial velocity ( $v_{o} = 0$ )

So time take to fall down,

$t = \sqrt{\frac{2d}{a} }$

$t = \sqrt{4}$

$t = 2$ sec

Now find horizontal distance travel by stone,

$x = vt$

$x = 20 \times 2$

$x = 40$ m

Therefore, the horizontal distance travel by stone is 40 m

3 0

3 years ago

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.

kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

$\displaystyle t=\sqrt{\frac{2h}{g}}$