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Brut [27]
3 years ago
14

Simple harmonic motion occurs when an object is displaced from its stable equilibrium position and the force or torque pushing i

t back toward equilibrium is ______ in displacement. Group of answer choices exponential sinusoidal quadratic linear
Physics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

force is of the LINEAR type

Explanation:

In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form

            F = - k (x-x₀)

where x₀ is the initial length of the spring.

Therefore we can see this force is of the LINEAR type

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3 0
3 years ago
Read 2 more answers
A 0.5 μF and a 11 μF capacitors are connected in series. Then the pair are connected in parallel with a 1.5 μF capacitor. What i
NISA [10]

Answer:

C_{eq}=1.97\ \mu F

Explanation:

Given that,

Capacitance 1, C_1=0.5\ \mu F

Capacitance 2, C_2=11\ \mu F

Capacitance 3, C_3=1.5\ \mu F

C₁ and C₂ are connected in series. Their equivalent is given by :

\dfrac{1}{C'}=\dfrac{1}{C_1}+\dfrac{1}{C_2}

\dfrac{1}{C'}=\dfrac{1}{0.5}+\dfrac{1}{11}

C'=0.47\ \mu F

Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :

C_{eq}=C'+C_3

C_{eq}=0.47+1.5

C_{eq}=1.97\ \mu F

So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.

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3 years ago
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Answer:

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2 years ago
Boyle's law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4l , the press
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Boyle's law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4l , the pressure is 720 kpa (kilopascals). What is the pressure when the volume is 10l ?

7 0
3 years ago
A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in
beks73 [17]

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

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3 years ago
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