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4 years ago

How does electricity work in a vacuum

Physics

1 answer:

Tpy6a [65]4 years ago

3 0

Answer:

Explanation:

Electricity is a flow of electrons. Electrons can flow across a vacuum. ... They need to leap because the vacuum is a perfect insulator and so there is no medium in which they can flow (like through a metal conductor) so they must aquire all of the energy necessary to cover the distance before they can escape the cathode.

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A gas mixture contains 320mg methane, 175 mg argon, 225 mg nitrogen (N2). The partial pressure of argon at 300K is 12.52 kPa. Wh

svet-max [94.6K]

Answer: The volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For methane:

Given mass of methane = 320 mg = 0.3 g (Conversion factor: 1 g = 1000 mg)

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane}=\frac{0.3g}{16g/mol}=0.019mol$

For argon:

Given mass of argon = 175 mg = 0.175 g

Molar mass of argon = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of argon}=\frac{0.175g}{40g/mol}=0.0044mol$

For nitrogen:

Given mass of nitrogen = 225 mg = 0.225 g

Molar mass of nitrogen = 28 g/mol

Putting values in equation 1, we get:

$\text{Moles of nitrogen}=\frac{0.225g}{28g/mol}=0.0080mol$

To calculate the volume of the mixture, we use the equation:

PV = nRT ......(2)

We are given:

Partial pressure of argon = 12.52 kPa

Temperature = 300 K

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

n = number of moles of argon = 0.0044 moles

Putting values in equation 2, we get:

$12.52kPa\times V=0.0044mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\V=\frac{0.0044\times 8.31\times 300}{12.52}=0.876L$

Now, calculating the total pressure of the mixture by using equation 2:

Total number of moles = [0.019 + 0.0044 + 0.0080] mol = 0.0314 mol

V= volume of the mixture = 0.876 L

Putting values in equation 2, we get:

$P\times 0.876L=0.0314mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\P=\frac{0.0341\times 8.31\times 300}{0.876}=89.36kPa$

Hence, the volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

5 0

3 years ago

Who discovered electromagnetic induction?

allsm [11]

Answer: Electromagnetic induction was discovered by Michael Faraday

7 0

4 years ago

You might say that this experiment was an attempt to build a scale, and then calibrate it against a scale that we trust (the ele

Allushta [10]

No.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.

<h3>What is a random error?</h3>

Random error is defined as the deviation of the total error from its mean value due to chance.

Random errors can result from the instrument not being precise or from mistakes by the researcher.

Random errors can be minimized by taking multiple readings and averaging the results.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.

Learn more about random errors at: brainly.com/question/22041172

3 0

3 years ago

Read 2 more answers

Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres i

Dennis_Churaev [7]

Answer:

Angular momentum of the system is 4.8 kg m^2/s

Explanation:

As we know that the angular momentum of the system of masses is given as

$L = 2I\omega$

here we have

$I = m(0.2 + 0.4)^2$

$I = 3(0.6)^2$

now we also know that

$\omega = \frac{v}{0.2 + 0.4}$

$0.6 \omega = 2 m/s$

now we have

$L = 2(2)(0.6)(2)$

$L = 4.8 kg m^2/s$

3 0

3 years ago

10 pts HELP ME PLEASE!? Transmission occurs when light passes straight through an object, thus meaning that light is not _____,

Alex_Xolod [135]

Transmission occurs when the light is not reflected or absorbed.

I think the question is also fishing for "refracted", but that's wrong. Light can be transmitted even though it's refracted, and I'd say it's the same for dispersed and scattered.

6 0

3 years ago