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2 years ago

How much work was required to move an object 3.0 meters if 75 joules of work were expanded

1 answer:

3 0

Work is measured in joules, so you're question was already answered! 75 joules of work was required.

However, if you're asking about the force that was required, you're answer would be 25 N of force.

work= force x distance
75= f x 3
75= 25 x 3

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Calculate the power required of a 60-kg person who climbs a tree 5 meters high in 10 seconds.

Alina [70]

Answer:

Explanation:

Power = Energy/time

-Don't have energy so I'm gonna solve for it

Gravitational Potential Energy = mass x gravity x height

= 60 kg x 9.8 m/s2 x 5m

= 2940 J

Power = Energy/time

=2940 J/10 s

= 294 W

3 0

2 years ago

as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?

GenaCL600 [577]

Answer:

False

Explanation:

A dominant trait is a trait that is inherited from parents. It is a trait that is obtained from a particular copy or type of a gene that overshadows or overwhelms the effects of another type or copy of that gene. Dominant traits are controlled by a single gene.

Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

5 0

3 years ago

A 12-kg piece of metal displaces 1.6 L of water when submerged. Part A Find its density. Express your answer to two significant

Tatiana [17]

Answer:

ρ = 7500 kg/m³

Explanation:

Given that

mass ,m = 12 kg

Displace volume ,V= 1.6 L

We know that

1000 m ³ = 1 L

Therefore V= 0.0016 m ³

When metal piece is fully submerged

We know that

mass = Density x volume

$m=\rho \times V$

Now by putting the values in the above equation

$\rho=\dfrac{12}{0.0016}\ kg/m^3$

ρ = 7500 kg/m³

Therefore the density of the metal piece will be 7500 kg/m³.

6 0

3 years ago

2 Ten identical lengths of wire are laid closely side-by-

Mice21 [21]

Answer:

(a) 0.71 mm

(b) 0.158 cubic cm

Explanation:

The width of one wire is the diameter of the wire.

(a) Let the diameter of each wire is d.

So, 10 d = 14.2 mm

d = 1.42 mm

radius of each wire, r = d/2 = 1.42/2 = 0.71 mm

(b) Length, L = 10 cm

The volume of the single wire is given by

$V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3$

7 0

2 years ago

A car traveling at 30 m/s speeds up to 35 m/s over a period of 5 seconds. What is the acceleration of the car?

Delvig [45]

Answer:

u =30 m/s

v = 35 m/s

t = 5 secs

Explanation:

a = (v- u)/t

a = (35-30)/5

a = 5/5

a = 1 m/s^2

PLS MARK BRAINLIEST

8 0

2 years ago