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3 years ago

a 25 resistor, a 55 resistor, and a 75 resistor are connected in parallel and placed across a 9.0battery.

Physics

1 answer:

lawyer [7]3 years ago

5 0

A) Equivalent Resistance= (1/25+1/55+1/75)^-1=14.0ohms(3s.f.)
b) Current=9.0V/14.0=0.644A(3s.f.)
c) Current through 25-resistor=9/25=0.360A
Current through 55-resistor=9/55=0.164A
Current through 75-resistor=9/75=0.120A
All answers are rounded off to 3 significant figures

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If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle

ad-work [718]

This question is incomplete, the complete question is;

The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10⁻⁹ N⋅m on an electric dipole oriented at 30° from the direction of the external field. The dipole moment of the dipole is 7.5 × 10⁻¹² C⋅m.

What is the magnitude of the external electric field?

If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?

Answer:

- the magnitude of the external electric field is 5333.3 N/C

- the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC

Explanation:

Given that;

Torque = 20.0 × 10⁻⁹ N⋅m

dipole moment = 7.5 × 10⁻¹²

∅ = 30°

The moment T of restoring couple is;

T = PEsin∅

E = T/Psin∅

we substitute

E = 20.0 × 10⁻⁹ N⋅m / (7.5 × 10⁻¹²) sin(30°)

E = 20.0 × 10⁻⁹ / 3.75 × 10⁻¹²

E = 5333.3 N/C

Therefore, the magnitude of the external electric field is 5333.3 N/C

The dipole moment is given by the expression;

p = ql

q = p / l

given that l = 2.5 mm = 0.0025 m

we substitute

q = 7.5 × 10⁻¹² / 0.0025

q = 3.0 × 10⁻¹² C ≈ 3 nC

Therefore, the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC

7 0

3 years ago

An electron of mass 9.11×10−31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to

dedylja [7]

Answer:

$F=1.509\times 10^{-16}N$

Explanation:

We have given that mass of electron $m=9.11\times 10^{-31}kg$

It is given that initial velocity u=0 m/sec

Final velocity v = $2.7\times 10^6m/sec$

Distance S = 2.2 cm = 0.022 m

According to third law of motion $v^2=u^2+2as$

$(2.7\times 10^6)^2=0^2+2\times a\times 0.022$

$a=165.68\times 10^{12}m/sec^2$

Accelerating force F is given by F = ma

So accelerating force $F=9.11\times 10^{-31}\times 165.68\times 10^{12}=1.509\times 10^{-16}N$

7 0

3 years ago

How much power is used in a machine that produces 15 Joules of work in 3 seconds? Use the formula P = W/t.

Marta_Voda [28]

P=w/t

w=15
t=3
therefore, 5 watts (b)

7 0

3 years ago

What would heat up faster and why? Water , wet sand , dry sand , or would it be no difference??

salantis [7]

In short, I’d say the answer is Dry Sand.

In solids, the intermolecular force of attraction is very high. Whereas, in liquids the intermolecular force of attraction is somewhat less than solids. ... so when you heat, less amount of heat can free the molecules in liquids than solids and hence they heat faster.

6 0

3 years ago

Read 2 more answers

A radar antenna is tracking a satellite orbiting the earth. At a certain time, the radar screen shows the satellite to be 118 km

ruslelena [56]

Answer:

x component 60.85 m

y component 101.031 m

Explanation:

We have given distance r = 118 km

Angle which makes from ground = 58.9°

(a) X component of distance is given by $r_x=rcos\Theta =118\times cos58.9=118\times 0.5165=118=60.85m$