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krek1111 [17]
3 years ago
10

a vehicle starts from rsst and after 10 seconds its velocity is 20m/s find the acceleration and the distance travelled.(step by

step only please)​
Physics
1 answer:
Naily [24]3 years ago
8 0

Answer:

<u>Acceleration is 2 m/s² </u>

<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>

Explanation:

From definition of acceleration, Acceleration is the rate of change in velocity.

• Simplifying the definition, or modifying it;

{ \boxed{ \rm{acceleration =  \frac{(final \: velocity - initial \: velocity)}{time} }}}

• Let's formulate symbols:

{ \boxed{ \rm{a =  \frac{v - u}{t} }}}

  • a is acceleration
  • v is final velocity, v = 20 m/s
  • u is initial velocity, u = 0 m/s [ at rest ]
  • t is time, t = 10 seconds

{ \rm{a =  \frac{20 - 0}{10}  =  \frac{20}{10} }} \\  \\{ \boxed{ \rm{ \: a = 2 \:  {ms}^{ - 2} }}}

Distance = ut + ½at²

Distance = (0 × 10) + (½ × 2 × 10²)

Distance = 0 + 10²

Distance = 100 meters

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