Answer:
Acceleration, 
Explanation:
It is given that,
Side of the square plate, l = 1 m
Charge on the square plate, 
Position of a proton, x = 1 cm
The electric field due to a parallel plate is given by :

Electric force is given by :
F = q E

e is the charge on electron
The acceleration of the proton can be calculated as :

m is the mass of proton



So, the acceleration of the proton is
. Hence, this is the required solution.
C
Unbalanced causes something to move because the net force is greater than zero
Answer:
Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T
Explanation:
Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :
......(1)
Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.
In this problem,
Current, I = 0.7 A
Length of wire, L = 0.62 m
Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m
Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m
Substitute these values in equation (1).

B = 6.99 x 10⁻⁶ T
It would be D I believe! Depending on the angle of the mirror and distance positioned!
If both particles have the SAME electrical charge, then they repel.
If they have DIFFERENT electrical charge, then they attract.
Protons have + charge .
Electrons have - charge .
So two protons (A) or two electrons (D) push apart.
One proton and one electron (C) pull together.