Answer:
Acceleration,
Explanation:
It is given that,
Side of the square plate, l = 1 m
Charge on the square plate,
Position of a proton, x = 1 cm
The electric field due to a parallel plate is given by :
Electric force is given by :
F = q E
e is the charge on electron
The acceleration of the proton can be calculated as :
m is the mass of proton
So, the acceleration of the proton is . Hence, this is the required solution.
Answer:
Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T
Explanation:
Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :
......(1)
Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.
In this problem,
Current, I = 0.7 A
Length of wire, L = 0.62 m
Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m
Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m
Substitute these values in equation (1).
B = 6.99 x 10⁻⁶ T