Answer:
Voltage, V = 0.0524 volts
Explanation:
Thickness of the membrane, 
Electric field strength, 
We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :


V = 0.0524 volts
So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.
D.) In order to calculate both of them, we must know the "FORCE" on the system.
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Answer:
The values is 
Explanation:
From the question we are told that
The slit distance is 
The wavelength is 
At the first half of the screen from the central maxima
The number of bright spot according to the condition for constructive interference is

For maximum number of spot 
So


Now for the both sides plus the central maxima we have

substituting values

