The “Compton effect” showed

2 answers:

8 0

The answer is the last choice, the particle nature of light. The compton effect showed that a charged electron scatters the photon results in decreased energy but increase in wavelength.

Yanka [14]3 years ago

3 0

Answer:

the particle nature of light

Explanation:

As we know that by the formula of Compton Effect we have

$\lambda' - \lambda = \frac{h}{mc}(1 - cos\theta)$

here in this formula we will say that when light of some given wavelength $\lambda$ incident on a particle then after deviating from the particle the light will change its direction by some angle $\theta$ .

And the wavelength of the particle will also changed to some different value as $\lambda'$

so here as per particle theory we will use the theory of momentum conservation as per which light of given momentum when hit a particle then it will transfer it momentum to the particle and deviated by some lesser momentum.

Due to decrease in momentum the change in wavelength of light is given by above formula

so this verify the particle nature of light

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olga55 [171]

Answer:

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Listed following are the names and mirror diameters for six of the world’s greatest reflecting telescopes used to gather visible

ziro4ka [17]

Answer:

Large binocular telescope, Keck 1 telescope, Hobby-Ebberly telescope, Subaru telescope, Gemini North telescope, Magellan 2 telescope

Explanation:

How much light a telescope can collect depends on its diameter, since in a bigger area more photons will be collected.

Remember that in a circle the area is defined as:

$A = \pi r^{2}$ (1)

Where A is the area and r is its radius.

However, the radius can be determined by means of its diameter.

$d = 2r$

$r = \frac{d}{2}$ (1)

Where d is its diameter.

An example of this is when a person is collecting raindrops with a bucket and with a cup. Since the bucket has a bigger area than the cup, it will collect more raindrops by unit of time. In this scenario the raindrops represent the photons.

To determine the light collecting area of each telescope, equation 2 will be replaced in equation 1.

$A = \pi (\frac{d}{2})^{2}$ (3)