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Alex
2 years ago
9

Calculate the mass in grams, in 2.28 mol of SO3 .

Chemistry
1 answer:
Ulleksa [173]2 years ago
7 0

The mass of 2.28 mol of SO₃ is 182.4 g.

<h3>What is mass?</h3>

Mass can be defined as the quantity of matter a body contains.

The S.I unit of mass is kilogram (kg). other units of mass include grams (g), milligram (mg), microgram (μg) etc.

<h3>What is a matter?</h3>

A matter is anything that has mass and occupies space. Matter exist in three states.

  • Solid state
  • Liquid state
  • Gaseous state

To calculate the mass of 2.28 mol of SO₃, we use the formula below.

Formula:

  • m = nM............. Equation 1

⇒ Where:

  • m = mass of SO₃
  • n = number of mole of SO₃
  • M = molar mass of SO₃

From the question,

Given:

  • n = 2.28 mol
  • M = 80 g/mol

Substitute these values into equation 1

  • m = 2.28×80
  • m = 182.4 g

Hence, the mass of 2.28 mol of SO₃ is 182.4 g.

Learn more about mass here: brainly.com/question/19385703

#SPJ1

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You would use a mass spectrometer
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irinina [24]

These are  diseases that affect primarily the lungs or any other part of the respiratory system.

<h3>What are respiratory disorders?</h3>

The term respiratory disorders refers to those diseases that affect primarily the lungs or any other part of the respiratory system. These are the diseases that prevent a person from breathing in and out normally and prevent the lungs from playing its usual role in gaseous exchange.

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8 0
1 year ago
How many moles of Ag+ ions are present in 10 ml of a 0.75 M AgNO3 solution?
lana66690 [7]

Answer:

b. 7.5 x 10^-3

Explanation:

To solve this problem we need to keep in mind the <em>definition of molarity</em>:

  • Molarity = moles of solute / liters of solution

With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:

  • First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L

Then we <u>calculate the moles of AgNO₃</u>:

  • moles of solute = Molarity * Liters of solution
  • 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃

<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.

5 0
3 years ago
A compound 21.20% nitrogen 6.06% hydrogen 24.30% sulfur and 48.45% oxygen. Write the empirical formula and name the compound?
egoroff_w [7]

Greetings!

<h3>To find the empirical formula you need the relative atomic mass of each element!</h3>

N = 14

H = 1

S = 32.1

<h3>You can simply change the percentages into full grams</h3>

N = 12.20

H = 6.06

S = 48.45

<h3>Then you use this to find the Number of moles = amount in grams / atomic mass</h3>

N = 12.20 ÷ 14 = 0.8714

H = 6.06 ÷ 1 = 6.06

S = 48.45 ÷ 32.1 = 1.541

<h3>Then divide each number of moles by the smallest value:</h3>

N = 0.8714 ÷ 0.8714 = 1

H = 6.06 ÷ 0.8714 = 6.9 ≈ 7

S = 1.541 ÷ 0.8714 = 1.76 ≈ 2


So that means that there are 1 Nitrogen, 7 hydrogen, and 2 sulfur. This means the empirical formula would be:

NH₇S₂


Hope this helps!

8 0
3 years ago
Consider the covalent bonding in the molecule acetylene [ah-SET-ihl-een], and assume that the carbon-carbon axis is the x-axis.
kirza4 [7]

Answer:

2py and 2pz orbitals

Explanation:

Each carbon atom still has two half-filled 2py and 2pz orbitals, which are perpendicular both to each other and to the line formed by the sigma bonds. These two perpendicular pairs of p orbitals form two pi bonds between the carbons, resulting in a triple bond overall (one sigma bond plus two pi bonds).

6 0
3 years ago
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