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k0ka [10]
3 years ago
14

if gas is sealed container has a pressure of 50 kpa at 300k, what will the pressure be if the temperature rises to 360 k

Chemistry
1 answer:
velikii [3]3 years ago
4 0

well if u add 300k to 360k your tempature will rise to 660k.


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What is the mass of 1.72 moles of BaSO4?
Fiesta28 [93]

Answer: 401.4g

Explanation:

The mass can be calculated by using the following mathematical expression for Moles ,which is:

Moles = Mass / Molar Mass

From the question given, Moles = 1.72, Molar mass of BaSO4 = 233.38g/mol, Mass =?

Making 'Mass' the subject of formula, we get:

Mass = Molar mass x Moles

= 233.38 x 1.72 = 401.4g

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How does temperature affect the state of matter
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A sample of methane occupies a volume of 370.0 ml at 25 oC and exerts a pressure of 1020 mm Hg. If the volume is allowed to expa
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744.9 mmHg ≅ 745 mmHg

Explanation:

The base to solve this, is the Ideal Gases Law. The mentioned formula is:

P . V = n . R . T

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For the first situation P₁ . V₁ = n₁. R . T₁

For the second situation P₂ . V₂ = n₂ . R . T₂

As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

We need to make Tº unit conversion:

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We replace data → (370 mL . 1020 mmHg) / 298K = (P . 510 mL) / 300 K

(377400 mL.mmHg / 298K) . 300 K = P . 510 mL

379932.8 mL . mmHg = P . 510 mL

(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg

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The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close
Natasha_Volkova [10]

Answer:

Ok:

Explanation:

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pH = pKa + log(A^-/HA) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

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6 0
3 years ago
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