if gas is sealed container has a pressure of 50 kpa at 300k, what will the pressure be if the temperature rises to 360 k

Use the equation to determine what mass of FeS must react to form 326 g of FeCl2.

iogann1982 [59]

Answer:

We need 226 grams of FeS

Explanation:

Step 1: Data given

Mass of FeCl2 = 326 grams

Molar mass FeCl2 = 126.75 g/mol

Step 2: The balanced equation

FeS + 2 HCl → H2S + FeCl2

Step 3: Calculate moles FeCl2

Moles FeCl2 = 326 grams / 126.75 grams

Moles FeCl2 = 2.57 moles

Step 4: Calculate moles FeS needed

For 1 mol H2S and 1 mol FeCl2 produced, we need 1 mol FeS and 2 moles HCl

For 2.57 moles FeCl2 we need 2.57 moles FeS

Step 5: Calculate mass FeS

Mass FeS = 2.57 moles * 87.92 g/mol

Mass FeS = 226 grams FeS

We need 226 grams of FeS

4 0

3 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

3 years ago

How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)

11Alexandr11 [23.1K]

$98.56 dm^3$ of oxygen at STP would be required to react completely with 38.8g of propane.

Given that :

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = $\frac{38.8}{44}$ = 0.88 mole

applying rule of balanced equations

1 mole of propane = 5 moles of oxygen

0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = $22.4 dm^3$

∴Total volume of oxygen required at STP = 22.4 * 4.4 = $98.56 dm^3$

Hence we can conclude that the volume of oxygen at STP required to react completely $98.56 dm^3$

Learn more : brainly.com/question/16998374

5 0

2 years ago

Metallic compounds are malleable. Which use of metallic bonds best represents this trait?

dem82 [27]

In metallic bonding, the valence electrons are free to move throughout the metal structure. Metallic bonding is the electrostatic attraction between the metal atoms or ions and the delocalized electrons. This is why atoms or layers are allowed to slide past each other, resulting in the characteristic properties of malleability and ductility.

8 0

3 years ago

Give an example of a two face mixture and describe how you would separate the substances

shutvik [7]

1.A two face mixture is a type of mixture in which the components of the mixture are in different states of matter. A good example of a two face mixture is carbonated soft drink. Carbonated soft drink is a mixture of carbon dioxide [which is a gas] and water [which is a liquid]. Another example of a two face mixture is the the mixture of iodine and sodium solution.

2. To separate the mixture of iodine and sodium solution the best separation method to use is sublimation.
Sublimation process is used to separate mixtures in which one of the component of the mixture can translate from the solid state to the gaseous state without passing through the liquid state. An example of a solid which can sublime is iodine.
The sublimation process involves heating the mixture. On heating, the sublime solid will turn to vapour and escape from the mixture leaving behind the other component. The sublime component will be regained when it cools down.

4 0

3 years ago