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Fiesta28 [93]
3 years ago
10

A compound has the formula C8H8 and does not contain any double or triple bonds. All the carbon atoms are chemically identical a

nd all the hydrogen atoms are chemically identical. Draw a Lewis structure for this molecule. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and charges), Atoms, and Templates toolbars. Include all hydrogen atoms.
Chemistry
1 answer:
Ann [662]3 years ago
7 0

Answer:

<h3>There's no way for C8H8 to exist without double bonds. To fulfill the rule of the octet, four bonds must be formed by each carbon. This can only be done in C8H8 through the formation of double bonds.</h3>

Explanation:

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Answer: B

Explanation: La respuesta es b porque su electricidad y no es un ácido.

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3 years ago
45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Alex Ar [27]

45.6 mL of 0.0600 M of Ba(OH)_{2} is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : M_{1} V_{1} =  M_{2} V_{2}                 ...( 1 )

Where  M_{1}= concentration of Ba(OH)_{2}  =  0.0600 M ( given )

M_{2} = concentration of HCl = ? ( to be find )

 V_{1}= volume of Ba(OH)_{2}  = 25.0 mL  ( given )

V_{2} = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  M_{2}  × 45.6 mL

M_{2}  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

to learn about concentration here ,

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7 0
1 year ago
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Y_Kistochka [10]

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muscular system

Explanation:

8 0
3 years ago
The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 x 10-15 s-1 at 298 K and a rate constant of 8
laiz [17]

Answer:

The correct answer is 160.37 KJ/mol.

Explanation:

To find the activation energy in the given case, there is a need to use the Arrhenius equation, which is,  

k = Ae^-Ea/RT

k1 = Ae^-Ea/RT1 and k2 = Ae^-Ea/RT2

k2/k1 = e^-Ea/R (1/T2-1/T1)

ln(k2/k1) = Ea/R (1/T1-1/T2)

The values of rate constant k1 and k2 are 3.61 * 10^-15 s^-1 and 8.66 * 10^-7 s^-1.  

The temperatures T1 and T2 are 298 K and 425 K respectively.  

Now by filling the values we get:  

ln (8.66*10^-7/3.61*10^-15) = Ea/R (1/298-1/425)

19.29 = Ea/R * 0.001

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3 0
3 years ago
What would happen to the air pressure on Earth's surface if the density of Earth's atmosphere were to suddenly double?A. The air
Sladkaya [172]

Answer:

B. The air pressure would increase 2X

Explanation:

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p = ρ × g × h

Pressure is force per unit area

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Pressure is directly proportional to density hence, any change in the density of a body directly affects the change in pressure of the body and vice versa.

4 0
2 years ago
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