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3 years ago

Identify whether the atom or ion in each equation shows oxidation or reduction

Chemistry

1 answer:

marissa [1.9K]3 years ago

6 0

Oxidation means that atom or ion loses electrons.
Reduction means that atom or ion takes electrons.

Cu²⁺ +2e⁻ ---> Cu⁰ , We can see that ion Cu²⁺ takes electrons, so this is reduction.
Fe⁰ ------> Fe⁺³ + 3e⁻, We can see that atom Fe lost electrons, so this is oxidation.

Reduction:
A., C., E.
Oxidation:
B., D.

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The question is incomplete, the complete question is:

The solubility of slaked lime, $Ca(OH)_2$ , in water is 0.185 g/100 ml. You will need to calculate the volume of $2.50\times 10^{-3}$ M HCl needed to neutralize 14.5 mL of a saturated

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<u>Explanation:</u>

Given values:

Solubility of $Ca(OH)_2$ = 0.185 g/100 mL

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Using unitary method:

In 100 mL, the mass of $Ca(OH)_2$ present is 0.185 g

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The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of $Ca(OH)_2$ = 0.0268 g

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Plugging values in equation 1:

$\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol$

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The chemical equation for the neutralization of calcium hydroxide and HCl follows:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O$

By the stoichiometry of the reaction:

Moles of $OH^-$ = Moles of $H^+$ = 0.000724 mol

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

Moles of HCl = 0.000724 mol

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Putting values in equation 2, we get:

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