All categories

3 years ago

What does ǵene of interest¨ mean ?

Chemistry

1 answer:

Airida [17]3 years ago

6 0

A fragment of who’s prudent and not the only one who is the a front

You might be interested in

Many appliances in your home and school use electrical energy. Which of these appliances is intended to convert electrical energ

Solnce55 [7]

Answer:

music amplifier or a loudspeaker

Explanation:

A music amplifier or a loudspeaker are a few devices that convert electrical energy into sound energy.

As it is a well known fact that energy can neither be created nor be destroyed it can only change from one form to the other. As here it is changing from electrical to sound.

6 0

2 years ago

A sample of 10K gold contains the following: 10.0g gold, 4.0g silver, 5.0g copper, and 5.0g nickel. What is the percent gold in

stellarik [79]

Answer:

oook

hi I am so sorry sorry sorry sorry I don't no answer

Explanation:

but you follow me and give me brainliest ok by by by by

6 0

3 years ago

Read 2 more answers

You have a particle of length 68 nm. What is this in meters? ( need help asap)

Bess [88]

Answer:

Explanation:

4 0

2 years ago

Balance this equation: CH4 +2O2--------> ___ CO2 + ___ H2O

Lubov Fominskaja [6]

Answer:

b-1 CO2+ 2H2O

5 0

3 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0

3 years ago