"The boron-nitrogen interaction in the studied molecules shows some similarities with the N→B bond in the H3N-BH3 molecule, formally understood as covalent-dative. ... The results show that all the studied BN bonds are triple, since three two-center orbitals have been obtained."
"Formation of a dative bond or coordinate bond between ammonia and boron trifluoride. When the nitrogen donates a pair of electrons to share with the boron, the boron gains an octet. ... In addition, a pair of non-bonding electrons becomes bonding; they are delocalized over two atoms and become lower in energy."
Try out answer C magnesium oxides melting point is almost 5 times higher than magnesium
The first one looks right
Answer:
An earthquake happens by the child being born from fat mama
Explanation:
Answer : The concentration of 
at equilibrium is, 0.244 M, 0.122 M and 1.267 M respectively.
Explanation :
The given chemical reaction is:
Initial conc. 0.439 0.317 0.877
At eqm. (0.439-x) (0.317-x) (0.877+2x)
As we are given:
The expression for equilibrium constant is:
![K=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
Now put all the given values in this expression, we get:
x = 0.195 and x = 0.690
We are neglecting the value of x = 0.690 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.195 M
The concentration of 
at equilibrium = (0.439-x) = (0.439-0.195) = 0.244 M
The concentration of 
at equilibrium = (0.317-x) = (0.317-0.195) = 0.122 M
The concentration of 
at equilibrium = (0.877+2x) = (0.877+2\times 0.195) = 1.267 M
