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3 years ago

Which of the following is a correct statement about collision theory?

Chemistry

2 answers:

Evgen [1.6K]3 years ago

7 0

<u>Answer: </u>The correct answer is option D.

<u>Explanation:</u>

The number of collisions that take place per second per unit volume of the reaction is called as collision frequency.

Particles undergoing only effective collision will lead to chemical reactions.

For a collision to be effective, the colliding molecules must have energy more than a particular value known as threshold frequency.

The factors which are responsible for the number of effective collisions are:

Energy factor which means that the colliding molecules must have energy greater than the threshold energy.
Orientation factor which means that the colliding molecules must have proper orientations at the time of collisions.

Hence, the correct answer is option D.

rjkz [21]3 years ago

3 0

The answer is D. Effective collisions lead to chemical reactions!

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Consider the balanced chemical equation for the combustion of methane (CH4).

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<h3>Answer:</h3>

89.6 L of O₂

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PLS HELP QUICK ALOTTT OF POINTS

timofeeve [1]

Answer:

$\boxed {\boxed {\sf 0.80 \ mol\ F}}$

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

$\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

$4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

Flip the ratio so the units of atoms of fluorine cancel each other out.

$4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}$

$4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }$

Condense into 1 fraction.

$\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F$

Divide.

$0.7970773829 \ mol \ F$

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$0.80 \ mol \ F$

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3 years ago

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