<u>Answer:</u>
<u>For a:</u> Yes, he has gained weight.
<u>For b:</u> The number of onions required is 1.
<u>Explanation:</u>
We are given:
Weight of Brandon checked earlier = 183 lb
Converting this into kilograms, we use the conversion factor:
1 kg = 2.205 lb
So, 
And, weight of Brandon measured at the health club = 85.0 kg
As, the weight at the health club is more than the previous measured weight. So, Brandon has gained weight.
We are given:
Amount of diced onions a recipe calls = 125 g
Mass of 1 onion = 4 oz
Converting the mass of 1 onion to ounces, we use the conversion factor:
1 oz = 28.35 g
So, 
To calculate the number of onions, we use the equation:


Hence, the number of onions required is 1.
Answer:
Volumen C6H8O6(sln) = 2.569 L ≅ 2.6 L
Explanation:
vitamin C ≡ ascorbic acid (C6H8O6)
∴ vitamin C/daily = 75.0 mg/d
∴ molar mass C6H8O6 = 176.12 g/mol
solution:
∴ <em>C</em> C6H8O6 = 0.002486 mol/L
⇒ ppm C6H8O6 = (0.002486 mol/L)*(176.12 g/mol)*(1000 mg/g)
⇒ ppm C6H8O6 = 437.834 mg/L
for a 15.0 day:
⇒ Volume C6H8O6(sln) = (75.0 mg/d)*(L/437.834 mg)*(15.0 d)
⇒ Volume C6H8O6(sln) = 2.569 L
Answer:
final concentration: Ca = 0.014 M
Explanation:
Velocity of reaction:
∴ α: order of reaction, assuming α = 1
∴ K = 0.249 s-1.......rate constant
∴ Cao = 0.050 M......initial concentration
∴ t = 5 s.......reaction time
⇒ δCa/δt = K*Ca
⇒ ∫δCa/Ca = K*∫δt
⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245
⇒ Cao/Ca = 3.473
⇒ Ca = 0.050/3.473
⇒ Ca = 0.014 M
Tin to Fluorine mass ratios:
1) For compound A:
38.5/12.3
= 3.13
2) For compound B:
56.5/36.2
= 1.56
The lowest whole number mass ratio is 2. It cannot be 1 because it is less than that required for compound B.