*The molality of a solution is calculated by taking the moles of solute and dividing by
the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until all the solid was gone. We
then made sure everything was well-mixed.
What would be the molality of this solution? Notice that my one liter of water weighs
1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).

3 0

2 years ago

How many micrograms (ug) are in 3.4 x 10^-5 ounces (oz)

marysya [2.9K]

Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

We are to convert from ounces to micrograms.

1ug = 1 x 10⁻⁶g

1oz = 28.35g

So we first convert to grams from oz then take to ug:

Solving:

1oz = 28.35g

3.4 x 10⁻⁵oz will then give 3.4 x 10⁻⁵ x 28.35 = 9.64 x 10⁻⁴g

So;

1 x 10⁻⁶g = 1ug

9.64 x 10⁻⁴g will give $\frac{9.64 x 10^{-4} }{1 x 10^{-6} }$ = 9.64 x 10²ug or 964ug

8 0

3 years ago