The energy of moving atoms is

Which describes a climate effect on the rate of weathering? Cold climates favor mechanical weathering. Chemical reactions occur

Alex777 [14]

Answer:

Cold climates favor mechanical weathering.

Explanation:

I just took the test and this is the correct answer!

5 0

2 years ago

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A rock weighing 15.0g is placed in a graduated cylinder, displacing the volume from 25.0 mL to 36.2 mL. What is the density of t

valina [46]

Density is defined as mass/volume, and the volume is 36.2-25 mL
so just substitute into the equation to get the answer.

Hope this helps.

6 0

3 years ago

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A bauxite mining company has got government permission to acquire agricultural land in a location to start surface mining activi

viktelen [127]

Answer:

make reclamation compulsory after bauxite has been removed

Explanation:

Available options:

choose other infertile and uninhabited locations for bauxite mining

allow agriculture and mining to take place simultaneously in the location

ask farmers in the location to help in mining bauxite

make reclamation compulsory after bauxite has been removed

The correct option and the best plan to solve the problem of permanent dislocation of farmers would be to make reclamation compulsory after the bauxite has been removed.

Reclamation would involve restoring the agricultural land back to its original status prior to the commencement of bauxite mining. By doing this, the farmers can return to their farmland after being temporarily displaced due to the mining activities.

6 0

3 years ago

"Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulf

Molodets [167]

Answer:

Can be produced 288mL of SO₂

Explanation:

Based in the reaction:

P₄S₃ + 8O₂ → P₄O₁₀ + 3SO₂

Where 1 mole of tetraphosphorus trisulfide reacts producing 3 moles of sulfur dioxide gas.

0.869g of tetraphosphorus trisulfide (Molar mass of P₄S₃: 220.09g/mol) are:

0.869g P₄S₃ ₓ (1mol / 220.09g) = 3.948x10⁻³ moles of P₄S₃

As 3 moles of SO₂ are produced per mole of P₄S₃:

3.948x10⁻³ moles of P₄S₃ ₓ (3 moles SO₂ / 1 mole P₄S₃) = 0.0118 moles SO₂

Using PV = nRT

V = nRT / P

Where n are 0.0118 moles, R gas constant (0.082atmL/molK), T absolute temperature (21.0°C + 273.15K = 294.15K), and P pressure (751torr / 760 = 0.988atm).

Replacing:

V = 0.0118molₓ0.082atmL/molKₓ294.15K / 0.988atm

V = 0.288L = 288mL

7 0

3 years ago

Consider separate 100.0 gram samples of each of the following: H2O, N2O, C3H6O2, CO2 Determine which 100.0 gram sample will have

vampirchik [111]

Answer : The sample $H_2O$ has greatest number of oxygen atoms.

The order of number of oxygen atoms from greatest to least will be:

$H_2O>CO_2>C_3H_6O_2>N_2O$

Explanation :

First we have to calculate the moles of $H_2O,N_2O,C_3H_6O_2\text{ and }CO_2$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}$

Molar mass of $H_2O$ = 18 g/mol

$\text{Moles of }H_2O=\frac{100.0g}{18g/mol}=5.55mol$

and,

$\text{Moles of }N_2O=\frac{\text{Mass of }N_2O}{\text{Molar mass of }N_2O}$

Molar mass of $N_2O$ = 44 g/mol

$\text{Moles of }N_2O=\frac{100.0g}{44g/mol}=2.27mol$

and,

$\text{Moles of }C_3H_6O_2=\frac{\text{Mass of }C_3H_6O_2}{\text{Molar mass of }C_3H_6O_2}$

Molar mass of $C_3H_6O_2$ = 74 g/mol

$\text{Moles of }C_3H_6O_2=\frac{100.0g}{74g/mol}=1.35mol$

and,

$\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}$

Molar mass of $CO_2$ = 44 g/mol

$\text{Moles of }CO_2=\frac{100.0g}{44g/mol}=2.27mol$

Now we have to calculate the number of oxygen atoms in $H_2O,N_2O,C_3H_6O_2\text{ and }CO_2$

In $H_2O$ :

As, 1 mole of $H_2O$ contains $1\times 6.023\times 10^{23}$ number of oxygen atoms

So, 5.55 mole of $H_2O$ contains $5.55\times 6.022\times 10^{23}=3.34\times 10^{24}$ number of oxygen atoms

In $N_2O$ :

As, 1 mole of $N_2O$ contains $1\times 6.023\times 10^{23}$ number of oxygen atoms

So, 2.27 mole of $N_2O$ contains $2.27\times 6.022\times 10^{23}=1.37\times 10^{24}$ number of oxygen atoms

In $C_3H_6O_2$ :

As, 1 mole of $C_3H_6O_2$ contains $2\times 6.023\times 10^{23}$ number of oxygen atoms

So, 1.35 mole of $C_3H_6O_2$ contains $2\times 1.35\times 6.022\times 10^{23}=1.62\times 10^{24}$ number of oxygen atoms

In $CO_2$ :

As, 1 mole of $CO_2$ contains $2\times 6.023\times 10^{23}$ number of oxygen atoms

So, 2.27 mole of $CO_2$ contains $2\times 2.27\times 6.022\times 10^{23}=2.73\times 10^{24}$ number of oxygen atoms

The order of number of oxygen atoms from greatest to least will be:

$H_2O>CO_2>C_3H_6O_2>N_2O$

5 0

3 years ago