Question

Which combination of formula, IUPAC name, and common name below is incorrect? Formula IUPAC Name Common Name (a) CHCl3 trichloromethane chloroform (b) CCl4 tetrachloromethane carbon tetrachloride (c) C6H5I iodobenzene phenyl iodide (d) CH3Cl chloromethane methyl chloride (e) CH2Cl2 dichloromethane methene chloride

Answer 1

Answer:

option (e), dichloromethane, methene chloride

Explanation:

(a)  $CHCl_3$

Common name:  chloroform

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Three chlorine atoms are present.

Therefore, IUPAC name: Trichloromethane

(b)  $CCl_4$

Common name:  Carbon tetrachloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Four chlorine atoms are present, chlorine atoms are named as prefixes.

Therefore, IUPAC name: tetrachloromethane

(c)  $C_6H_5I$

Common name: Phenyl iodide

IUPAC name:

The given compound is an aryl halides. Aryl haildes are named as haloarenes. The prefix halo is placed before aromatic hydrocarbon. Here, prefix is iodo and aromatic hydrocarbon is benzene.

Therefore, IUPAC name of the compound is iodobenzene.

(d)  $CH_3Cl$

Common name:  Methyl chloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

One chlorine atom is present.  

Therefore, IUPAC name: chloromethane

(e)  $CH_2Cl_2$

Common name: Methylene chloride

IUPAC name: one carbon atom, therefore, root word is meth.

Its is saturated compounds, so add ane after root word.

Two chlorine atoms are present, chlorine atoms are named as prefixes.

Therefore, IUPAC name: dichloromethane.

Therefore, the correct option is option (e), dichloromethane, methene chloride