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Tatiana [17]
2 years ago
10

You start with 1 L of CO2 at standard temperature and pressure in a closed container. If you raise the temperature of the gas, t

he pressure will
Increase
Remain the same
Decrease
Chemistry
1 answer:
pychu [463]2 years ago
8 0

Answer:

Increase

Explanation:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

If the initial temperature and pressure is standard,

Pressure = 1 atm

Temperature = 273.15 K

then we increase the temperature to 400.0 K, The pressure will be,

1 atm / 273.15 K = P₂/400.0K

P₂ = 1 atm × 400.0 K / 273.15 K

P₂ = 400.0 atm. K /273.15 K

P₂ = 1.46 atm

Pressure is also increase from 1 atm to 1.46 atm.

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Salt water is, A. a mixture

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How much energy would be released if 450.0 g of the substance completely reacted with oxygen?
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1.1853 kJ

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The chemical reaction that occurs in a gas grill is the combustion of propane, C3H8. Write a balanced equation for this reaction
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A crystal of potassium permanganate is placed in a beaker of water. The purple colour of potassium permanganate gradually spread
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<h3>What are the two conclusions given out in the method of diffusion?</h3>

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6 0
2 years ago
The pressure in a bicycle tire is 1.34atm at 33.0 ° C. At what temperature will the pressure inside the tire be 1.60atm?
Y_Kistochka [10]

Answer:

92.37°C

Explanation:

Assuming the volume remains the same in both the states ( bicycle tire).

Then as per ideal gas equation

P_1/T_1 = P_2/T_2

where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states

Given:

P1 = 1.34 atm, T1 = 33.0 ° C = 306K

P2 = 1.60 atm, T2 = ?

1.34/306 = 1.60/T_2

⇒ T2 = 1.60×306/1.34

= T2= 365.37K= 92.37°C

8 0
3 years ago
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