You start with 1 L of CO2 at standard temperature and pressure in a closed container. If you raise the temperature of the gas, t
1 answer:
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The mass of a sample of alcohol is found to be = m = 367 g
Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.
Explanation:
The Energy of the sample given is q = 4780
We are required to find the mass of alcohol m = ?
Given that,
The specific heat given is represented by = c = 2.4 J/gC
The temperature given is ΔT = 5.43° C
The mass of sample of alcohol can be found as follows,
The formula is c =
We can drive value of m bu shifting m on the left hand side,
m =
mass of alcohol (m) =
m = 367 g
Therefore, The mass of the given sample of alcohol is
m = 367g
It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.
Answer:
will be 90054 J
Explanation:
Number of moles = (mass)/(molar mass)
Molar mass of = 134.45 g/mol
So, 1.00 g of =
of
= 0.00744 mol of
0.00744 mol of produces 670 J of heat
So, 1 mol of produces
of heat or 90054 J of heat