Data:
Molar Mass of NaOH = 40 g/mol
Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules
6.02*10²³y = 0.270*10²³


Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH


Answer:
The mass is 1.6 grams
<h3>Answer:</h3>
There is One electrophilic center in acetyl chloride.
<h3>Explanation:</h3>
Electrophile is defined as any specie which is electron deficient and is in need of electrons to complete its electron density or octet. The main two types of electrophiles are those species which either contain positive charge (i.e. NO₂⁺, Cl⁺, Br⁺ e.t.c) or partial positive charge like that contained by the sp² hybridized carbon of acetyl chloride shown below in attached picture.
In acetyl chloride the partial positive charge on sp² hybridized carbon is generated due to its direct bonding to highly electronegative elements *with partial negative charge) like oxygen and chlorine, which tend to pull the electron density from carbon atom making it electron deficient and a good electrophile for incoming nucleophile as a center of attack.
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Answer:
2–methylpropene.
Explanation:
To successfully name the compound given in the question, we must observe the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, let us determine the name of the compound. This is illustrated below:
1. The functional group of the compound is the double bond i.e the compound is an alkene.
2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.
3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.
4. Therefore, the name of the compound is:
2–methylpropene