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3 years ago

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Un cajón rectangular de madera sin tapadera mide 3m de largo, 2.5 m de ancho y 1 m de altura. Se arroja al agua y flota . Sí el

cajón pesa 48 000 N, ¿ Cuánto de su altura queda bajo el agua?

1 answer:

Cerrena [4.2K]3 years ago

7 0

Answer:

CBTIS 118?

Explanation:

CBTIS 118 ES LA RESPUESTA

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Identical objects, Object X and Object Y, are tied together by a string and placed at rest on an incline, as shown in the figure

goblinko [34]

The slope of the velocity time graph of an object moving with constant acceleration is constant

It will take approximately <u>3 seconds</u> for the center of mass of Object X to reach point J near the bottom of the incline

The reason why the above time value is correct is given as follows:

Known parameters:

Initial velocity of the objects, u = 0

The graph in the question is a straight line graph with data points

(0, 0), (0.5, 1.0), (1.0, 2), (3.0, 6), and (3.5, 7)

Given that the slope of the velocity-time graph is constant, we have that the acceleration is constant and is given as follows;

$a = \dfrac{\Delta v}{\Delta t } = \dfrac{v_2 - v_1}{t_2 - t_1}$

Therefore;

$a = \dfrac{6 - 2}{3.0 - 1.0} = 2$

The acceleration, a ≈ 2 m/s²

The distance from the center of mass of the Object X to the point J near the bottom = 9 m

The equation for distance travelled is given as follows;

$s = u\cdot t + \dfrac{1}{2} \cdot a \cdot t^2$

Which gives;

$9 = 0\times t + \dfrac{1}{2} \times 2 \times t^2 = t^2$

t = √9 = 3

The time it will take the center of mass of Object X to reach point J near the bottom of the incline is t = <u>3 seconds</u>

Learn more about motion under constant acceleration here:

brainly.com/question/16391598

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3 years ago

How much is Coulomb's constant ?

kakasveta [241]

Answer:

8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2

Explanation:

Exact number is 8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2

7 0

3 years ago

Pun zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que caminar hay un insta

Mars2501 [29]

Answer:

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

Explanation:

Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:

$\sigma = \frac{W}{n\cdot A_{T}}$ (Eq. 1)

Donde:

$\sigma$ - Presión, medida en libras por pulgada cuadrada.

$W$ - Peso de la persona, medida en libras.

$n$ - Cantidad de tacos en los zapatos, adimensional.

$A_{T}$ - Área del taco, medida en pulgadas cuadradas.

Si conocemos que $W = 180\,lb$ , $n = 20$ y $A_{T} = 0.01\,in^{2}$ , la presión es:

$\sigma = \frac{180\,lb}{(20)\cdot (0.01\,in^{2})}$

$\sigma = 900\,psi$

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

3 0

3 years ago

The Earth revolves around the sun in a nearly circular orbit. Please select the best answer from the choices provided T F

Verdich [7]

The Earth does revolves around the sun in a nearly circular orbit so the answer is T

6 0

3 years ago

Read 2 more answers

A bead slides without friction around a loopthe-loop. The bead is released from a height 18.6 m from the bottom of the loop-the-

12345 [234]

Answer:

See explanation

Explanation:

To do this, you need to use energy conservation. The sum of kinetic and potential energies is the same at all points along the path so, you can write the expression like this:

1/2mv1² + mgh1 = (1/2)mv2² + mgh2

Where:

v1 = 0 because it's released from rest

h1 = 18.6 m

v2 = speed we want to solve.

h2 = height at point A. In this case, you are not providing the picture or data, so, I'm going to suppose a theorical data to solve this. Let's say h2 it's 12 m.

Now, let's replace the data in the above expression (assuming h2 = 12 m). Also, remember that we don't have the mass of the bead, but we don't need it to solve it, because it's simplified by the equation, therefore the final expression is:

1/2v1² + gh1 = 1/2v2² + gh2

Replacing the data we have:

1/2*(0) + 9.8*18.6 = 1/2v² + 9.8*12

182.28 = 117.6 + 1/2v²

182.28 - 117.6 = v²/2

64.68 * 2 = v²

v = √129.36

v = 11.37 m/s

Now, remember that you are not providing the picture to see exactly the value of height at point A. With that picture, just replace the value in this procedure, and you'll get an accurate result.

3 0

3 years ago