The displacement of Edward in the westerly direction is determined as 180.27 km.
<h3>Displacement of Edward</h3>
The displacement of Edward is calculated as follows;
R² = a² + b² - 2abcosθ
R² = 150² + 200² - 2(150 x 200) x cos60
R² = 32500
R = 180.27 km
Thus, the displacement of Edward in the westerly direction is determined as 180.27 km.
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Answer:
no both remains same...
Explanation:
because the work done is given by the product of the both the masses added (m+m) Displacement
and second time when you carry the bags individually it comes out to be the same m×displacement + m×displacement
I wanna say A.
Not a 100% sure but this is what i think
hope it helps!
Answer:
Tension on each chain: 30.28N
Explanation:
We start by drawing a free-body diagram of all the forces acting on the flower pot. These are:
1) the weight of the flower pot which is the product of the pot's mass time the acceleration of gravity "g" (pictured in green and represented by in the diagram), and
2) the two tensions in the chains, which since they are symmetric, are of the same size, pictured in red color and represented by the letter "T" in the diagram.
We also decompose the tensions T in two components each (a vertical component V and a horizontal component h) which are pictured in blue.
All vertical forces must cancel out since the object is in static equilibrium, so:
The horizontal components h are equal, and since they act in opposite directions, they indeed cancel out.
Now to calculate the tension, we use the fact that we know the angle between T and the component V. They in fact are related via the cosine of the angle because they are the hypotenuse and the adjacent side in a right angle triangle:
Answer:
Se obtienen 2,27 gramos de metanol.
Explanation:
La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:
CO + 2H₂ → CH₃OH
Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:
En donde:
m: es la masa
M: es el peso molecular
Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:
Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.
Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.
Por lo tanto, se obtienen 2,27 gramos de metanol.
Espero que te sea de utilidad!