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Hoochie [10]
3 years ago
12

the line on the position time graph show the velocites of different vehicles which line represents a vehicle moving at constant

velocity
Physics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

For some mysterious reason, we can't see the graph.

On a position/time graph, constant velocity is represented by a <em>straight line</em>.  Depending on the velocity, the line may be sloping up, sloping down, or horizontal.  The only thing the line on the graph <u><em>CAN't</em></u> be is vertical.

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Which model of the atom has electrons traveling in specific paths around the nucleus? Bohr's model Rutherford's model Thomson's
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Bohr's Model

Explanation:

I took the test and got it right

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What is the animal behavior where organisms imitate another organism or environment in some way?
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Mimicry. This is when oraganisms imitate another oraganism whether it be physical or behavoioral.

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An object object travels 24 meters in the +x direction for 3.5 seconds, and then immediately travels some distance in the -x dir
kicyunya [14]

Answer:

The distance in -x axis is 39.77 m

Explanation:

Given that,

Distance in +x axis = 24 m

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v=\dfrac{d}{t}

Put the value into the formula

v=\dfrac{24}{3.5}

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v=\dfrac{x}{9.3-3.5}

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x=\dfrac{24}{3.5}\times5.8

x=39.77\ m

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7 0
3 years ago
deals with the concepts that are important in this problem. A grasshopper makes four jumps. The displacement vectors are (1) 31.
Troyanec [42]

(a) 46.6 cm

To calculate the total displacement, we need to resolve each vector along the x- and y- direction.

In the following, we take:

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- North as positive y-direction, South as negative y-direction

Vector A:

A_x = -31.0 cm\\A_y = 0

Vector B:

B_x = -(32.0 cm) cos 34.0^{\circ}=-25.6 cm\\B_y = -(32.0 cm) sin 34.0^{\circ} = -17.9 cm

Vector C:

C_x = (16.0 cm)cos 57.0^{\circ} =8.7 cm\\C_y = -(16.0 cm)sin 57.0^{\circ} =-13.4 cm

Vector D:

D_x = (16.0 cm) cos 75.0^{\circ} =4.1 cm\\D_y = (16.0 cm) sin 75.0^{\circ} =15.5 cm

So the components of the total displacement are:

R_x = -31.0 cm - 25.6 cm +8.7 cm +4.1 cm =-43.8 cm\\R_y = 0-17.9 cm -13.4 cm +15.5 cm =-15.8 cm

So the magnitude of the total displacement is:

R=\sqrt{R_x^2 + R_y^2}=\sqrt{(-43.8 cm)^2+(-15.8 cm)^2}=46.6 cm

(b) 19.8 degrees south of west

First of all, let's notice that:

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This means that the angle will be given by

\theta = tan^{-1} (\frac{R_y}{R_x})

where we have

R_x = -43.8 cm\\R_y = -15.8 cm

Substituting, we find

\theta = tan^{-1} (\frac{-15.8 cm}{43.8 cm})=19.8^{\circ}

and this angle is south of west.

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