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2 years ago

Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2

Mathematics

1 answer:

Levart [38]2 years ago

7 0

Answer:

the desired equation is y = (-1/3)x + 6

Step-by-step explanation:

Let the given line be A: y=3x+2

The slope of line A is m = 3.

The slope of any line B which is perpendicular to line A is the negative reciprocal of the slope of A: m = -(1/3).

The particular perpendicular line that passes through (3, 5) is then

5 = (-1/3)(3) + b, which simplifies to 5 = -1 + b, or b = 6.

Thus, the desired equation is y = (-1/3)x + 6

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Simplest form<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20-%20%20%5Cfrac%7B3%7D%7B8%7D%20%20" id="TexFormula

raketka [301]

$\frac{3}{5}$ - $\frac{3}{8}$ = $\frac{3 * 8}{5 * 8}$ - $\frac{3 * 5}{8 * 5}$ = $\frac{24}{40}$ - $\frac{15}{40}$ = $\frac{9}{40}$

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3 years ago

Hii anyone mind helping me with this question :D

Digiron [165]

0.0045, Bc that negative exponent makes the decimal point move to the left!

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2 years ago

I need to figure out how many solutions does the system of equations below have.

Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

$\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}$

$\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8$

$\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}$

$\frac{5x}{63} = \frac{82}{9}$

$45x = 63*82$

Both a and b are different of 0, so the system has one solution.

6 0

2 years ago

A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hotdogs and 13 dozen

Kisachek [45]

Answer:

Hotdogs are $12.00 for the dozen or $1.00 each

Bratwursts are $18.00 for the dozen or $1.50 each

Step-by-step explanation:

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2 years ago

The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

zhuklara [117]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}$

3 0

3 years ago