Question

Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2

Answer 1

Answer:

the desired equation is y = (-1/3)x + 6

Step-by-step explanation:

Let the given line be A:  y=3x+2

The slope of line A is m = 3.

The slope of any line B which is perpendicular to line A is the negative reciprocal of the slope of A:  m = -(1/3).

The particular perpendicular line that passes through (3, 5) is then

5 = (-1/3)(3) + b, which simplifies to 5 = -1 + b, or b = 6.

Thus, the desired equation is y = (-1/3)x + 6