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kondor19780726 [428]
3 years ago
7

How many meters is a 10 by 3 foot flag?

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0

Answer: 30

Step-by-step explanation:

You might be interested in
If f(1) = 160 and f(n+ 1) = -2f(n), what is f(4)?
sertanlavr [38]
F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320

Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640

Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280

Final Answer: -1280

7 0
4 years ago
Read 2 more answers
If you roll a number cube 12 times, about how many times would you expect to roll a 5 or 6
Marrrta [24]
You have a 1/3 chance each time you role So 1/3 x 12 = 4 times that you would role a 5 or a 6
6 0
3 years ago
It takes 12 apples to make 2 cups of apple sauce. If 72 apples are used, what is the greatest number of cups of apple sauce that
Klio2033 [76]

Answer:

12

Step-by-step explanation:

If 12 apples makes 2 cups, we can assume that 6 apples make 1 cup.

Take the number of apples and divide it by 6 in order to find out the number of cups that can be made.

3 0
3 years ago
In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. Three of the 8 are in one family
lianna [129]
There are 14 chairs and  8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆  x 3! 

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

4 0
3 years ago
Fritz benjamin buys a car costing $12300. He agrees to make payment at the end of each month period for 8 years. He pays 7.2% in
loris [4]
12300=X[((1-(1+(0.072/12)^(-12*8))/(0.072/12)]
Solve for x
X=168.92
4 0
3 years ago
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