Question: When is this due?
Answer:
y=8
Step-by-step explanation:
Answer:
P(Y = 0) = 0.09
P(Y = 1) = 0.4
P(Y = 2) = 0.32
P(Y = 3) = 0.19
Step-by-step explanation:
Let the events be:
Wednesday
Thursday
Friday
Saturday
Their corresponding probabilities are
Since 
= number of days beyond Wednesday that it takes for both magazines to arrive(so possible values are 0, 1, 2 or 3)
The possible number of outcomes are therefore 
The values associated for each of the outcomes are as follows:
The probability mass function of is,
![P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19](https://tex.z-dn.net/?f=P%28Y%20%3D%200%29%20%3D%200.3%280.3%29%20%3D%200.09%5C%5CP%28Y%20%3D%201%29%20%3D%20P%5B%28W%2C%20T%29%20or%20%28T%2C%20W%29%20or%20%28T%2C%20T%29%5D%5C%5C%3D%20%5B0.3%280.4%29%20%2B%200.3%280.4%29%20%2B%200.4%280.4%29%5D%5C%5C%3D%200.4%5C%5C%5C%5CP%28Y%20%3D%202%29%20%3D%20P%5B%28W%2C%20F%29%20or%20%28T%2C%20F%29%20or%20%28F%2C%20W%29%20or%20%28F%2C%20T%29%20or%20%28F%2C%20F%29%5D%5C%5C%3D%20%5B0.3%280.2%29%20%2B%200.4%280.2%29%20%2B%200.2%280.3%29%20%2B%200.2%280.4%29%20%2B%200.2%280.2%29%5D%5C%5C%3D%200.32%5C%5C%5C%5CP%28Y%20%3D%203%29%20%3D%20P%5B%28W%2C%20S%29%20or%20%28T%2C%20S%29%20or%20%28F%2C%20S%29%20or%20%28S%2C%20W%29%20or%20%28S%2C%20T%29%20or%20%28S%2C%20F%29%20or%20%28S%2C%20S%29%5D%5C%5C%3D%20%5B0.3%280.1%29%20%2B%200.4%280.1%29%20%2B%200.2%280.1%29%20%2B%200.1%280.3%29%200.1%280.4%29%20%2B%200.1%280.2%29%20%2B%200.1%280.1%29%5D%5C%5C%3D%200.19)
To find the common ratio, start at the end and divide terms:
(8/9) / (4/3) = (2/3)
(4/3) / 2 = (2/3)
2 / 3 = (2/3)
The ratio is 2/3
We immediately note that 3 and 9 are multiples. Therefore, they are factorable. 9 goes into 3 three times, and 3 goes into three 1 time. Therefore, we can take out three from the whole expression to get 3(c - 3).
