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2 years ago

How many meters are equal to 18 kilometers?

Mathematics

2 answers:

amid [387]2 years ago

7 0

Answer:

18000

Step-by-step explanation:

goldfiish [28.3K]2 years ago

5 0

Step-by-step explanation:

18000 m = 18 kilometres

1 kilometres = 1000m

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Find the range of f(x)=x+3 <br> when the domain (2,4,6)

jarptica [38.1K]

<u>f(x) = x + 3</u>
f(2) = 2 + 3
f(2) = 5

f(4) = 4 + 5
f(4) = 9

f(6) = 6 + 5
f(6) = 11

{(2, 5), (4, 9), (6, 11)}

5 0

2 years ago

5 to 7 and please solve with equations thx

padilas [110]

Answer:

Step-by-step explanation:

5) x + 5.4 < -1.6

x < -1.6 - 5.4

x < -7

6) x + 7.5 > -2.5

x > -2.5 - 7.5

x > -10

7) 3 ≤ 1/3 + x

x ≥ 3 - 1/3

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4 0

2 years ago

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Solve kx + 8 = 4 for x.

Harlamova29_29 [7]

K×x+8=4
k×x=4-8
k×x=-4
x=-4/k

7 0

2 years ago

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Function or not a function

Aliun [14]

Answer:

not a function

Step-by-step explanation:

6 0

2 years ago

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A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%

andre [41]

Answer: a) 683 b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

a) Given : Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=\pm1.96$

Margin of error : $E=0.03$

Formula to calculate the sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683$

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067$

Hence, the required sample size would be 1067 .

3 0

2 years ago