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Arada [10]
3 years ago
15

A diathermy machine, used in physiotherapy, generates electromagnetic radiation that gives the effect of "deep heat" when absorb

ed in tissue. One assigned frequency for diathermy is 915.00 MHz. What is the wavelength of this radiation
Physics
2 answers:
olga nikolaevna [1]3 years ago
5 0

Answer:

The wavelength of the given radiation is 0.327 m

Explanation:

The wavelength and the frequency of a wave are related by the formula, given below:

v = fλ

where.

v = speed of wave

f = frequency of wave = 915 MHz = 915000000 Hz

λ = wavelength of the wave = ?

For the electromagnetic radiations we know that:

v = c = speed of light = 3 x 10^8 m/s

Therefore,

c = fλ

λ = c/f

λ = (300000000 m/s)/(915000000 Hz)

<u>λ = 0.327 m</u>

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

The wavelength of this radiation = 0.3279 m

Explanation:

For a wave, the speed (v), frequency (f) and the wavelength (λ) are related through the relation

v = fλ

f is given in the question as 915 MHz = (915 × 10⁶) Hz = (9.15 × 10⁸) Hz

v = speed of light = (3.0 × 10⁸) m/s (since electromagnetic waves/radiation travel with the speed of light)

λ = ?

λ = (v/f)

λ = (3.0 × 10⁸)/(9.15 × 10⁸)

λ = 0.3279 m

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A man pushes on a piano with mass 190 kgkg ; it slides at constant velocity down a ramp that is inclined at 18.0 ∘∘ above the ho
creativ13 [48]

Answer:

The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.

Explanation:

Given:

Mass of the piano (m) = 190 kg

Inclined angle (\theta) = 18 degree

Considering gravity, g = 9.8 ms^-^2

And

Using, sin(18) =0.30 and cos(18)=0.95

<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>

We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.

a.

When the man pushes it parallel to the incline.

Balancing the forces as  \sum F=0 .

⇒ F+mgsin(\theta) =0

⇒ F=-mgsin(\theta)

⇒ Here it is negative as the force is acting downward.

⇒ Plugging the values of mass (m) and angle (\theta) .

⇒ F=190\times 9.8\times sin(18)

⇒ F=575.38 N

b.

When the force is parallel to the floor.

⇒ Fcos(\theta)=mgsin(\theta)

⇒ F=\frac{mgsin(\theta)}{cos(\theta)}

⇒ Plugging the values.

⇒ F=\frac{190\times 9.8\times sin(18)}{cos(18)}

⇒ F=605 N

So,

The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.

6 0
3 years ago
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