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Dennis_Churaev [7]
3 years ago
15

Explain the correspondence that lets us easily translate between linear motion and rotational motion. What are the linear analog

ues of the rotational quantities we have discussed in lecture (i.e. angle, angular velocity, angular acceleration, moment of inertia)? Where does the correspondence seem to fail?
Physics
1 answer:
RideAnS [48]3 years ago
4 0

Explanation:

The linear analog of angle is angle itself.

The linear analog of angular velocity is linear velocity.

ω is angular velocity, therefore linear velocity is given by v

∴ for linear velocity, v^{2} = u^{2}+2.a.S

   for angular velocity, \omega_{f}^{2}  = \omega _{i}^{2}+2.a.S

The linear analog of angular acceleration is acceleration.

α is angular acceleration whereas as a is linear acceleration.

∴ for linear acceleration, v = u + a.t

  for angular acceleration, \omega_{f}= \omega _{i}+\alpha .t

The linear analog of moment of inertia is mass.

I is moment of inertia and m is mass,

∴ for linear analog, F = m.a

  for angular analog, τ - I.α

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What is the density of an object with mass of 60 g and a volume of 2cm3
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2 years ago
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3 years ago
Your friend, who is in a field 100 meters away from you, kicks a ball towards you with an initial velocity of 16 m/s. Assuming t
LekaFEV [45]

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Time, t = 5.355 seconds

Explanation:

Given the following data;

Distance = 100 m

Initial velocity = 16 m/s

Deceleration = 1 m/s²

To find the time, we would use the second equation of motion;

But since the ball is decelerating, it's acceleration would be negative.

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

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Solving the quadratic equation using the quadratic formula;

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Substituting into the equation, we have;

x = \frac {-32 \; \pm \sqrt {32^{2} - 4*1*(-200)}}{2*1}

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x = \frac {-32 \pm \sqrt {1824}}{2}

x = \frac {-32 \pm 42.71}{2}

x_{1} = \frac {-32 + 42.71}{2}

x_{1} = \frac {10.71}{2}

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We do not need the negative value of x, so we proceed.

Therefore, time = 5.355 seconds

3 0
3 years ago
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