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barxatty [35]
3 years ago
10

Is smoke a element, compound , heterogenous mixture or a solution??

Chemistry
2 answers:
ale4655 [162]3 years ago
8 0
Smoke is a heterogeneous mixture.

Hope it helps.
Anna71 [15]3 years ago
6 0
Heterogeneous mixture
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The proximate reason for the uptake by plants of nutrients like ammonium nitrate is?
Blizzard [7]

The proximate reason for the uptake by plants of nutrients like ammonium nitrate is homeostatis

<h3>What is homeostasis?</h3>

Homeostasis refers to an organism's ability to regulate various physiological processes to keep internal states steady and balanced.

<h3>How does plant perform homeostatis?</h3>

As water leaves the plant tissues into the atmosphere, it takes energy with it in the form of heat.

Much like when we sweat, this allows the plant to cool and maintain homeostasis.

Similarly, the same process allows plants to  absorb nutrient like ammonium nitrate.

Thus, the proximate reason for the uptake by plants of nutrients like ammonium nitrate is homeostatis.

Learn more about homeostatis here: brainly.com/question/1046675

#SPJ1

8 0
1 year ago
Find the natural abundance of Si-30.
nataly862011 [7]
<span> First you need to know how many isotopes there are of silicon, and its average atomic units (look at periodic table). Then make up a system of equations to solve for it. Theres 3 stable silicon isotopes (28, 29, 30) so you will need to have 3 equations. You must be given the percent abundance of at least one of the isotopes to solve because here I can only see 2 equations (numbered down below) set x = percent abundance of si-28 y = percent abundance of si-29 z = percent abundance of si-30 since all of silicon atoms account for 100% of all silicon: x + y + z = 100% = 1 therefore: 1) x = 1 - y - z You also have 2) 28x + 29y + 30z = average atomic mass you can substitute x so that equation becomes: 28 (1 - y - z) + 29y + 30z = average atomic mass See how you have 2 variables here? You cant go on until you know the value of one isotope already or you have given a clue which you can derive the third equation</span>
5 0
3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
2 years ago
(Brainliest) Please Help! Please do not give me a random, gibberish answer or I will report you and give you a low rating theref
nataly862011 [7]

Answer:

3.10g

Explanation:

Please see the attached picture for the full solution.

3 0
3 years ago
A solution was made by dissolving 5.10 mg of hemoglobin in water to give a final volume of 1.00 ml. the osmotic pressure of this
Assoli18 [71]

The molecular weight of hemoglobin can be calculated using osmotic pressure

Osmotic pressure is a colligative property and it depends on molarity as

πV = nRT

where

π = osmotic pressure

V = volume = 1mL = 0.001 L

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 25°C = 25 + 273 K = 298 K

Putting values we will get value of moles

moles=\frac{\pi V}{RT}=\frac{0.00195X0.001}{0.0821X298}mol

we know that

moles=\frac{mass}{molarmass}

Therefore

molarmass=\frac{mass}{moles}=\frac{5.10X10^{-3}g}{7.97X10^{-8}}=6.399X10^{4}g

5 0
2 years ago
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