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irakobra [83]
2 years ago
6

____________is not an effect of heat

Chemistry
2 answers:
Olenka [21]2 years ago
7 0
C- contraction
Not an affect of heat
devlian [24]2 years ago
5 0

Answer:

c. contraction

Explanation:

Heating will cause substances to expand, or change their state (like solid to liquid) or it may be a chemical reaction.

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What are the correct coefficients when this chemical equation is<br> balanced? *<br> P4 + 02 P2O5
finlep [7]

Answer:

What are the correct coefficients when this chemical equation is

balanced? *

P4 + 02 P2O5

<h2>1, 5, 2</h2>

Explanation:

For this reaction we have a combination reaction. Balancing Strategies: This combination reaction is a lot easier to balance and if you can get an even number of oxygen atoms on the reactants side of the equation.

3 0
2 years ago
Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed
masya89 [10]

(A) 7.28\cdot 10^{-10} m

The De Broglie wavelength of an electron is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

v=1.00\cdot 10^6 m/s

and its mass is

m=9.11\cdot 10^{-31} kg

So, its momentum is

p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s

And substituting into (1), we find its De Broglie wavelength

\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m

(B) 1.16\cdot 10^{-34}m

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s

And so, the De Broglie wavelength of the ball is given by

\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m

(C) 9.02\cdot 10^{-9}m

The location of the first intensity minima is given by

y=\frac{L\lambda}{a}

where in this case we have

y=0.492 cm = 4.92\cdot 10^{-3} m

L = 1.091 is the distance between the detector and the slit

a=2.00\mu m=2.00\cdot 10^{-6}m is the width of the slit

Solving the formula for \lambda, we find the wavelength of the electrons in the beam:

\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m

(D) 7.35\cdot 10^{-26}kg m/s

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

p=\frac{h}{\lambda}

where here we have

\lambda=9.02\cdot 10^{-9}m is the wavelength

Substituting into the formula, we find

p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s

7 0
3 years ago
What is the source of energy for an earthquake
MA_775_DIABLO [31]
Seismic waves is the energy of and earthquake aka Elastic Energy
3 0
3 years ago
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Which property of waves is the distance between one point on a wave and that same point on the wave next to it?
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The answer is B, wavelength
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I know the paper is blurry but can anyone explain any of the questions from 76-80?
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Answer:try to make a good pic please I have ideas about the topic

3 0
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