B............................................................................
First, consider the steps to heat the sample from 209 K to 367K.
1) Heating in liquid state from 209 K to 239.82 K
2) Vaporaizing at 239.82 K
3) Heating in gaseous state from 239.82 K to 367 K.
Second, calculate the amount of heat required for each step.
1) Liquid heating
Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol
=> number of moles = 12.62 g / 17 g/mol = 0.742 mol
Heat1 = #moles * heat capacity * ΔT
Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J
2) Vaporization
Heat2 = # moles * H vap
Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J
3) Vapor heating
Heat3 = #moles * heat capacity * ΔT
Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J
Third, add up the heats for every steps:
Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J
Fourth, divide the total heat by the heat rate:
Time = 22,466.3 J / (6000.0 J/min) = 3.7 min
Answer: 3.7 min
Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the balanced chemical equation
H₂ + F₂ → 2HF
<h3>What is Ideal Gas ?</h3>
An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.
It is expressed as:
PV = nRT
where,
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant
T = temperature
Here,
P = 1 atm [At STP]
V = 110 ml = 0.11 L
T = 273 K [At STP]
R = 0.0821 [Ideal gas constant]
Now put the values in above expression
PV = nRT
1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K
n = 0.0049 mol
<h3>How to find the concentration of resulting solution ? </h3>
To calculate the concentration of resulting solution use the expression
= 0.032 M
Thus from the above conclusion we can say that Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.
Learn more about the Ideal Gas here: brainly.com/question/25290815
#SPJ4
Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
<h3>Charles's Law</h3>
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.
Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:
V÷ T= k
Considering an initial state 1 and a final state 2, it is satisfied:
V1÷ T1= V2÷ T2
<h3>Volume at 65°C</h3>
In this case, you know:
- V1= 22.4 L
- T1= 0 C= 273 K
- V2= ?
- T2= 65 C= 338 K
Replacing in Charles's law:
22.4 L÷ 273 K= V2÷ 338 K
Solving:
(22.4 L÷ 273 K) ×338 K= V2
<u><em>V2= 27.73 L</em></u>
Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
Learn more about Charles's law:
brainly.com/question/4147359
#SPJ1
