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maks197457 [2]
4 years ago
13

How do you do this? i dont get the valence shell or anything after that

Physics
1 answer:
levacccp [35]4 years ago
3 0

Answer:

can u tell what you are doing

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If a person is moving to the right, the net force acting upon her cannot be balanced
Svetach [21]

Yeah its True!!  Its unbalanced because the unbalance fore are unequeal in size and opposite in direction.

5 0
3 years ago
What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high (formula:pe=mgh)
yKpoI14uk [10]

The potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

<h3>What is potential energy?</h3>

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

The potential energy is mainly depending upon the height of the object. when the cyclist is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.

The potential energy is found as;

PE=mgh

PE=25 kg× 9.81 m/s² ×3 m

PE= 735.75 J.

Hence, the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

To learn more about the potential energy, refer to the link;

brainly.com/question/24284560

#SPJ1

5 0
2 years ago
Suppose you want to use this human engine to lift a 2.35 kg box from the floor to a tabletop 1.30 m above the floor. How much mu
morpeh [17]

Answer:

The increase in the gravitational potential energy is 29.93 joules.

Explanation:

Given that,

Mass of the box, m = 2.35 kg

It is lifted from the floor to a tabletop 1.30 m above the floor, h = 1.3 m

We need to find the increase the gravitational potential energy. Initial it will placed at ground i.e. its initial gravitational potential is equal to 0. The increase in the gravitational potential energy is given by :

U=mgh

U=2.35\ kg\times 9.8\ m/s^2\times 1.3\ m

U = 29.93 Joules

So, the increase in the gravitational potential energy is 29.93 joules. Hence, this is the required solution.

6 0
4 years ago
A particle moves along the x axis from the origin. The magnitude of the position vector at time t is
Maurinko [17]

1) The average velocity is -2.1\cdot 10^5 m/s

2) The instantaneous velocity is 64t-260t^3

Explanation:

1)

The average velocity of an object is given by

v=\frac{d}{t}

where

d is the displacement

t is the time elapsed

In this problem, the position of the particle is given by the function

x(t) = 32t^2 - 65t^4

where t is the time.

The position of the particle at time t = 6 sec is

x(6) = 32(6)^2 - 65(6)^4=-83,088 m

While the position at time t = 12 sec is

x(12)=32(12)^2-65(12)^4=-1,343,232 m

So, the displacement is

d=x(12)-x(6)=-1,343,232-(-83,088)=-1,260,144 m

And therefore the average velocity is

v=\frac{-1,260,144 m}{12 s- 6 s}=-2.1\cdot 10^5 m/s

2)

The instantaneous velocity of a particle is given by the derivative of the position vector.

The position vector is

x(t) = 32t^2 - 65t^4

By differentiating with respect to t, we find the velocity vector:

v(t) = x'(t) = 2\cdot 32 t - 4\cdot 65 t^3 = 64t - 260 t^3

Therefore, the instantaaneous velocity at any time t can be found by substituting the value of t in this expression.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

6 0
4 years ago
What is the net force needed to accelerate a 21.4 kg grocery sack upward at 1.5 m/s2?
marshall27 [118]

Answer:

32.1 N Please Give Brainliest

Explanation:

force = mass x acceleration

8 0
3 years ago
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