Question

You jump off a platform 134 m above the Neuse River. After you have free-fallen for the first 40 m, the bungee cord attached to your ankles starts to stretch. You continue to descend another 80 m before coming to rest. Assume that your mass is 100 kg. What is your acceleration when you are momentarily at rest at the lowest point in the jump

Answer 1

Answer:

The acceleration at lowest point is 19.62 m/s^2

Explanation:

Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.

Lets Assume

Constant of string is K

By using the conservation of energy we will have the following equation

1/2 x 80^2 x K = m x 9.81 x 120

3200 K =  1177.2 m

K = 1177.2 m / 3200

K = 0.368 m

At the lowest point we will have

a = ( K x X - m x g ) / m

a = ( 0.368 m x 80 - m x 9.81 ) / m

a = 19.62 m / s^2

So, the acceleration at lowest point is 19.62 m/s^2

Answer 2

Answer:

19.62 m/s^2

Explanation: