Answer:
V = 365643.04 m/s
Explanation:
mass of the sun = 1.99 x 10^{30} kg
mass of M1 = mass of M2 = 6.95 solar mass = 6.95 x 1.99 x 10^{30} = 13.8305x 10^{30} kg
orbital period of each star (T) = 2.20 days = 2.20 x 24 x 60 x 60 =190,080 s
gravitational constant (G) = 6.67 x 10^{-11} N m2/kg2
orbital speed (V) = 
we need to find the orbital radius (r) before we can apply the formula above and we can get it from Kepler's third law,
x k
where
- k =
(take note that π is shown as
)
making r the subject of the formula we now have
(take note that π is shown as
)

r = 1.38 x 10^{10} m
Now that we have the orbital radius (r) we can substitute all required values into the formula for orbital speed
orbital speed (V) = 

V = 365643.04 m/s
Momentum = mass • velocity
M = m • v
Speed is a scalar quantity
Velocity is a vector quantity
That is truly the only difference
<span>The difference between work done by the gravitational force on descending and ascending objects is that for descending objects a terminal velocity will be reached where the object will not fall any faster that it already is. For an ascending object, its velocity will come down the longer gravity has an effect on it until the object begins to descend and the velocity of an ascending object will continue to change the longer gravity has an effect on it.</span>
Total force = Frope - mg = 309-300
total force = ma
9 = 30a
Answer:
The velocity of the leaf relative to the jogger is 5 m/s.
Explanation:
Given that,
Velocity of jogger wrt to the ground, 
velocity of leaf wrt the ground, 
We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.