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3 years ago

Can someone explain to me how this problem is done? Thank you so much.

1 answer:

6 0

Use the equation displacement=v(initial)-1/2at^2
v=velocity a=acceleration t=time
So displacement=3.5-(1/2)(.25)(3)^2= 2.375m

they should give you this equation on a sheet or something
hope this helps

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The amount of work done by the person is equal to 120 Joules.

<u>Given the following data:</u>

Force = 34 Newton.

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To calculate the amount of work done by the person at a total height of 2 meters:

<h3>How to calculate work done.</h3>

In Science, work done is calculated by multiplying force and the displacement experienced by an object.

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$Work\;done = force \times displacement$

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Read more on work done here: brainly.com/question/22599382

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3 years ago

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BlackZzzverrR [31]

<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (1)

$V_{f}=V_{o}+at$ (2)

Where:

$V_{f}$ is the final velocity of the plane (the takeoff velocity in this case)

$V_{o}=0$ is the initial velocity of the plane (we know it is zero because it starts from rest)

$a=5m/s^{2}$ is the constant acceleration of the plane to reach the takeoff velocity

$d=1800m$ is the distance of the runway

$t$ is the time

Knowing this, let's begin with (1):

${V_{f}}^{2}=0+2(5m/s^{2})(1800m)$ (3)

${V_{f}}^{2}=18000m^{2}/s^{2}$ (4)

$V_{f}=134.164 m/s$ (5)

Substituting (5) in (2):

$134.164 m/s=0+(5m/s^{2})t$ (6)

Finding $t$ :

$t=26.8 s$ This is the time needed to take off

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3 years ago