The coefficient of expansion is 13 * 10^-6 m per meter length.per oK
The temperature difference = 42 - - 8 = 50 oC
delta T = (42 + 273) - (-8 + 273) = 50 oK
delta L = L * 13* 10^6 m/oK
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m
Answer:
The appropriate solution is "61.37 s".
Explanation:
The given values are:
Boat moves,
= 10 m/s
Water flowing,
= 1.50 m/s
Displacement,
d = 300 m
Now,
The boat is travelling,
= ![10+1.50](https://tex.z-dn.net/?f=10%2B1.50)
= ![11.5 \ m/s](https://tex.z-dn.net/?f=11.5%20%5C%20m%2Fs)
Travelling such distance for 300 m will be:
⇒ ![v = \frac{d}{t} \ sot \ t](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20%5C%20sot%20%5C%20t)
![=\frac{d}{v}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bd%7D%7Bv%7D)
On putting the values, we get
![=\frac{300}{11.5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B300%7D%7B11.5%7D)
![=26.08 \ s](https://tex.z-dn.net/?f=%3D26.08%20%5C%20s)
Throughout the opposite direction, when the boat seems to be travelling then,
= ![10-1.50](https://tex.z-dn.net/?f=10-1.50)
= ![8.5 \ m/s](https://tex.z-dn.net/?f=8.5%20%5C%20m%2Fs)
Travelling such distance for 300 m will be:
⇒ ![v=\frac{v}{t} \ sot \ t](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bv%7D%7Bt%7D%20%5C%20sot%20%5C%20t)
![=\frac{d}{v}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bd%7D%7Bv%7D)
On putting the values, we get
![=\frac{300}{8.5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B300%7D%7B8.5%7D)
![=35.29 \ s](https://tex.z-dn.net/?f=%3D35.29%20%5C%20s)
hence,
The time taken by the boat will be:
= ![26.08+35.29](https://tex.z-dn.net/?f=26.08%2B35.29)
= ![61.37 \ s](https://tex.z-dn.net/?f=61.37%20%5C%20s)
Answer:
4.25 m/s
Explanation:
They walked the first distance at 5.50 m/s, then the same distance at 3 m/s.
Since the distances are equal, the average speed is simply the average of 5.50 and 3.
(5.50 + 3) / 2 = 4.25
Her average speed over the entire trip is 4.25 m/s.
Answer:
Chemical change
Explanation:
A chemical change is what happens. The food digested changes smell due to some enzyme the has acted on the food which catalyzes the rate of digestion. The enzymes acts on the food in order to speed up the rate of the reaction (digestion) and in turn causing the smell.
Answer:
4.25 J
Explanation:
Given that
mass of plastic ball = 11 g
Mass of plastic ball = 0.011 kg
velocity of ball = 29 m/s
We know that from work power energy theorem
![W_{all}=Change\ in\ kinetic\ energy\ of\ system](https://tex.z-dn.net/?f=W_%7Ball%7D%3DChange%5C%20in%5C%20kinetic%5C%20energy%5C%20of%5C%20system)
We know that kinetic energy of moving mass given as
![KE=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
Now by pitting the values
![KE=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![KE=\dfrac{1}{2}\times 0.011\times 29^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.011%5Ctimes%2029%5E2)
KE= 4.25 J
So the work done on the ball is 4.25 J