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sashaice [31]
3 years ago
15

You pull with a force of 255 N on a piece of luggage of mass 68 kg, but it does not move. If the coefficient of friction between

the luggage and the floor is 0.7, what is the force of static friction acting on the luggage?
Physics
2 answers:
VLD [36.1K]3 years ago
8 0

Answer:

the other guy was right, the answer is 255

Explanation:

STALIN [3.7K]3 years ago
3 0

The force of static friction acting on the luggage =255 N

Explanation:

Applied force= 255 N

mass of luggage=68 kg

coefficient of friction= μ=0.7

Normal force=N = mg

N= 68(9.8)=666.4 N

now the force of friction is given by

Ff= μN

Ff=0.7 (666.4)

Ff=466.5 N which is greater than the applied force.

When the applied force is less than the force of friction, in that case

force of friction= applied force

Thus the force of station friction acting on the luggage = 255 N

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Is a 10 year old supposed to be doing algebra
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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
Nookie1986 [14]

The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

a = 25 / 50

<h3>a = 0.5 m/s²</h3>

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

8 0
2 years ago
A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
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Answer:

Positive z direction.

Explanation:

The magnetic force acting on the electron is given by the formula as :

F=q(v\times B)

q is the charge on proton

v is the speed of proton

B is the magnetic field

It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,

q = +e

v = vi

B = Bj

F=e(v\ i\times B\ j)

Since, i\times j=k

F=(evB)\ k

So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".

8 0
3 years ago
A 50g man is walking at a speed of 4m/s. what is the kinetic energy of the walker?
Phantasy [73]
We have: K.E. = 1/2 mv²
Here: m = 50 g = 0.05 Kg
v = 4 m/s

Substitute their values, 
K.E. = 1/2 * 0.05 * 4²
K.E. = 1/2 * 0.05 * 16
K.E. = 0.4 J

In short, Your Answer would be 0.4 Joules

Hope this helps!
4 0
3 years ago
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