Answer:
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Explanation:
Given:
Diameter of sphere,
d= 0.29 cm
Charge ,
To Find:
Electric potential , V = ?
Solution:
Electric Potential at point surface is given as,
Where,
V= Electric potential,
ε0 = permeability free space = 8.85 × 10–12 F/m
Q = Charge
r = Radius
Substituting the values we get
Therefore,
The potential (in V) near its surface is 186.13 Volt.
An ideal air-filled parallel plate capacitor with plate a separation of 4.0 cm has a plate area of 0.040 m2. what is the capacitance of this capacitor with air between these plates<u> 8.9 pF.</u>
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its plates.
The capacitance of a parallel plate capacitor depends on area of each plate, dielectric medium between the plates and distance between the plates.
The amount of energy stored in a plate capacitor is given by
⇒ U = ,
where, Q is the stored charge and C is the capacitance,
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Answer:
No, the pendulum's period of oscillation does not depend on initial angular displacement.
Explanation:
Given that,
For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.
We know that,
The time period of pendulum is defined as
Where, l = length of pendulum
g = acceleration due to gravity
So, The time period of pendulum depends on the length of pendulum and acceleration due to gravity.
It does not depend on the initial angular displacement.
Hence, No, the pendulum's period of oscillation does not depend on initial angular displacement.