at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle
Answer:
given,
mass of copper = 100 g
latent heat of liquid (He) = 2700 J/l
a) change in energy
Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (300 - 4)
Q = 11153.63 J
He required
Q = m L
11153.63 = m × 2700
m = 4.13 kg
b) Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (78 - 4)
Q = 2788.41 J
He required
Q = m L
2788.41 = m × 2700
m = 1.033 kg
c) Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (20 - 4)
Q = 602.90 J
He required
Q = m L
602.9 = m × 2700
m =0.23 kg
Hello, I see you are in a jam. Lemme help.
1.) True
2.) True
3.) True
4.) True
5.) True
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Speed = 11000 m/s = 11km/s
D = 380000 km,
t = D/s = 380000 km/ 11km/s
t = 34 545.45 seconds.
Let the directions are defined by vectors as following
East = + x direction
West = - x direction
North = + y direction
South = - y direction
upwards = + z direction
downwards = - z direction
So here we are given that it moves
1). 10 m East
2). 9 m South
3). 3 m North
4). 2 m down
So we can write it as




Now total displacement will be given as



now the magnitude of the displacement will be


so the magnitude of displacement will be 11.8 m