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slega [8]
3 years ago
10

Look online for the growth of the trunk of a tree. Estimate how much time does it take for a water oak to grow one inch in diame

ter. Estimate the growth rate over a year
Mathematics
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

Explained

Step-by-step explanation:

The trunk of a tree grows in two different ways, first in height and second in diameter.Usually tree grows one ring per year in diameter. So, counting the number of rings we can determine the age of a tree. Both height and diameter growth does not occur at the same rate. Tree grows more in height than in their diameter. Mature trees usually grows 1 inch in diameter every year.

Water oak gains 24 inches in height  every year and  1.5 inch growth in diameter annually, meaning if we divide 1.5 inches by 12 months we gets 0.125 inches growth monthly. So a water oak tree needs only 8 months to grow 1 inch in diameter.

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Which table identifies the one-sided and two-sided limits of function at x = 2?​
Yuliya22 [10]

Answer:

Table 3

Step-by-step explanation:

Check table three;

lim\:_{x\to \:2^-}\:f\left(x\right)=\:4

lim\:_{x\to \:2^+}\:f\left(x\right)=\:1

Since the left hand limit (lim\:_{x\to \:2^-}\:f\left(x\right)) is not equal to the right hand limit (lim\:_{x\to \:2^+}\:f\left(x\right)),  the limit as x approaches to 2 does not exist.

Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2

6 0
3 years ago
A bird traveled 4 miles north before stopping to rest. The bird then flew 2,640 yards south in search of food. Finally, it flew
ra1l [238]
7 and 1/2 mile because 2,640=1.5 miles
4-1.5=2.5+5=7.5
8 0
2 years ago
Please help<br><br>solve this but don't spam<br>​
vfiekz [6]
9x-8=9x-3/2 X3
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2(9x-2)=27x-9
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4 0
2 years ago
Which shows the expression x^2-1/x^2-x in simplest form
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Answer:

\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}

Step-by-step explanation:

\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}

4 0
3 years ago
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ExtremeBDS [4]

Answer:  

¡Estoy teniendo un buen día!

8 0
2 years ago
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