Just want to double check does that look right to y’all or is it another answer ? Please help !!!!!
1 answer:
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Answer:
And we can use the following excel code to find it:
"=NORM.DIST(-2.4,0,1,TRUE)"
Step-by-step explanation:
Data given and notation
n=100 represent the random sample taken
estimated proportion of interesst
is the value that we want to test
represent the significance level
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the proportion is lower than 0.5:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The next step would be calculate the p value for this test.
Since is a left tailed test the p value would be:
And we can use the following excel code to find it:
"=NORM.DIST(-2.4,0,1,TRUE)"