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almond37 [142]
3 years ago
5

Each dimension of a larger rectangular field is 4.5 times greater than a smaller rectangular field. If it costs $176 to seed the

smaller field, how much would it cost to seed the larger field with the same type of seeds?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
Since the cost of seeding the field is proportional to the area of the field. Then we could calculate the cost of seeding the larger field by scaling up the cost of seeding the smaller field.


The area of the larger field is (4.5)(4.5) = 20.25 times the area of the smaller field, and so the cost of feeding should be 20.25 times.

Therefore, cost = 20.25(176) = $3564.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Step-by-step explanation:

<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

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now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

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Equating 'y' powers ,we get

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we get

2 n=6

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verification:-

substitute m=2 and n=3 , we get

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(2 x^{3} y^2)^2 = 4 x^6 y ^4\\

4 x^6 y^4 = 4 x^6 y^4

both are equating so m= 2 and n=3

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